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2 years ago

The sum of the two numbers is 52 and the difference is 28. Calculate the numbers.

Mathematics

1 answer:

Phantasy [73]2 years ago

6 0

Let's set these two numbers as 'a' and 'b'

Now, let's set up equations based on the information known:

the sum of the two numbers is 52 --> a + b = 52
the difference is 28 --> a - b =28

Equations

a + b = 52 -- equation 1
a - b = 28 -- equation 2

Solve:

(Equation 1) + (Equation 2)

2a = 80

a = 40 -- equation 3

(Equation 3)

40 + b = 52

b = 12

So a = 40 and b = 12

Hope that helps!

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How does the value of b affect the graph of the equation?

slamgirl [31]

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3 years ago

how many legs do 10 people have? if two people dont have legs. one person has 3 legs and one person has one leg. and mary has a

Ganezh [65]

So here is the answer. Normally, 10 people have 20 legs since each person has 2 legs each. But given the scenario that two people don't have legs, this would mean 20 minus 4, is 16 legs. Then one person has 3 legs, 16 plus 3 and it is 19. And then, another person has one leg, 19 plus 1 is 20. Therefore, the total legs would still be 20. Hope this helps. The dog does not count.

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3 years ago

Read 2 more answers

For each system of equations, drag the true statement about its solution set to the box under the system?

natta225 [31]

Answer:

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

Step-by-step explanation:

* Lets explain how to solve the problem

- The system of equation has zero number of solution if the coefficients

of x and y are the same and the numerical terms are different

- The system of equation has infinity many solutions if the

coefficients of x and y are the same and the numerical terms

are the same

- The system of equation has one solution if at least one of the

coefficient of x and y are different

* Lets solve the problem

∵ y = 4x + 2 ⇒ (1)

∵ y = 2(2x - 1) ⇒ (2)

- Lets simplify equation (2) by multiplying the bracket by 2

∴ y = 4x - 2

- The two equations have same coefficient of y and x and different

numerical terms

∴ They have zero equation

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

∵ y = 3x - 4 ⇒ (1)

∵ y = 2x + 2 ⇒ (2)

- The coefficients of x and y are different, then there is one solution

- Equate equations (1) and (2)

∴ 3x - 4 = 2x + 2

- Subtract 2x from both sides

∴ x - 4 = 2

- Add 4 to both sides

∴ x = 6

- Substitute the value of x in equation (1) or (2) to find y

∴ y = 2(6) + 2

∴ y = 12 + 2 = 14

∴ y = 14

∴ The solution is (6 , 14)

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

3 0

3 years ago

Simplify the radical expression. 1. √45 2. √180x^2 3.√490y^5 w^6

lara [203]

#1) 3√5
#2) 6x√5
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8 0

3 years ago

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Given h (t) = negative 2 (t + 5) squared + 4, find h (negative 8)

kaheart [24]

Answer:

h(-8)= -14

Step-by-step explanation:

h(-8)= -2(-8 + 5)^2 + 4

h(-8)= -2(-3)^2 + 4

h(-8)= -2(9) + 4

h(-8)= -18 + 4

h(-8)= -14

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3 years ago