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Given : f(x)= 3|x-2| -5
f(x) is translated 3 units down and 4 units to the left
If any function is translated down then we subtract the units at the end
If any function is translated left then we add the units with x inside the absolute sign
f(x)= 3|x-2| -5
f(x) is translated 3 units down
subtract 3 at the end, so f(x) becomes
f(x)= 3|x-2| -5 -3
f(x) is translated 4 units to the left
Add 4 with x inside the absolute sign, f(x) becomes
f(x)= 3|x-2 + 4| -5 -3
We simplify it and replace f(x) by g(x)
g(x) = 3|x + 2| - 8
a= 3, h = -2 , k = -8
Answer:
Step-by-step explanation:
47 and 48 are the integers.
Step-by-step explanation:
Let,
x and x+1 be the integers, therefore, according to statement;

2nd Integer = x+1
2nd Integer = 47+1
2nd integer = 48
47 and 48 are the integers.
Keywords: Addition
Learn more about addition at:
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Standard form is Ax + By = C with A, B, C being constants