Answer:
The irrational conjugate theorem states that if a polynomial equation has a root (a + √b), then we can say that the conjugate of (a + √b), i.e. (a - √b) will also be another root of the polynomial.
Step-by-step explanation:
The irrational conjugate theorem states that if a polynomial equation has a root (a + √b), then we can say that the conjugate of (a + √b), i.e. (a - √b) will also be another root of the polynomial.
For example, if we consider a quadratic equation x² + 6x + 1 = 0, then two of its roots are - 3 + √8 and - 3 - √8 and they are conjugate of each other. (Answer)
5x - 2y = -6 ⇒ 10x - 4y = -12
2x - 1y = 1 ⇒ <u>10x - 5y = 5</u>
y = -17
5x - 2(-17) = -6
5x + 34 = -6
<u> - 34 - 34</u>
<u>5x</u> = <u>-40</u>
5 5
x = -8
(x, y) = (-8, -17)
2x + 3y = 432 ⇒ 10x + 15y = 2160
5x + 2y = 16 ⇒ <u>10x + 4y = 32</u>
<u>11y</u> = <u>2128</u>
11 11
y = 193.4545455
2x + 3(193.4545455) = 432
2x + 580.3636364 = 432
<u> - 580.3636364 - 580.3636364</u>
<u>2x</u> = <u>-148.3636364</u>
2 2
x = -74.1818182
(x, y) = (-74.1818184, 193.4545455)
Answer:
The picture that does not contain enough information to prove that ΔABC = ΔDEF is
(3) Picture (3)
Step-by-step explanation:
The given information in picture (3) is the Angle-Side-Side of ΔABC corresponds with the Angle-Side-Side of ΔDEF,
However, the condition of Angle-Side-Side of ΔABC, is not sufficient to prove that ΔABC is congruent to ΔDEF congruency because the length of the unknown side can have two possible values
Answer: f(-2) = -6
Step-by-step explanation: f(-2) = -2 -4
f(-2) = -6
2D-a^2=2
2(a√2) -a^2=2
a^2-2√2*a+2=0
2a= 2√2 + √(8-4*2) = 2√2
hence, perimeter = 4a = 2*2a=2*2√2 = 4√2
