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3 years ago

Temperatures in __________ are usually seen in scientific work.

Mathematics

1 answer:

Vanyuwa [196]3 years ago

3 0

Answer:

What I think is that it's usually Kelvin and Celia are the once usually seen in scientific work

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At a deli 56 sandwiches were sold during lunchtime. Twenty five percent of the sandwiches sold were tuna salad sandwiches. How m

mr Goodwill [35]

Well if %100 was sold you'd have none. %50 you have half which i

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4 years ago

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v={x,y,z} such that the points satisfies x-2y+3z=0. is v vector space? if not,find all for which v is not a victor space

atroni [7]

Yes, the set of vectors

V = {(x, y, z) : x - 2y + 3z = 0}

is indeed a vector space.

Let u = (x, y, z) and v = (r, s, t) be any two vectors in V. Then

x - 2y + 3z = 0

and

r - 2s + 3t = 0

Their vector sum is

u + v = (x + r, y + s, z + t)

We need to show that u + v also belongs to V - in other words, V is closed under summation. This is a matter of showing that the coordinates of u + v satisfy the condition on all vectors of V:

(x + r) - 2 (y + s) + 3 (s + t) = (x - 2y + 3z) + (r - 2s + 3t) = 0 + 0 = 0

Then V is indeed closed under summation.

Scaling any vector v by a constant c gives

cv = (cx, cy, cz)

We also need to show that cv belongs to V - that V is closed under scalar multiplication. We have

cx - 2cy + 3cz = c (x - 2y + 3z) = 0c = 0

so V is need closed under scalar multiplication.

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3 years ago

22% of what number is 33?

ivolga24 [154]

The correct answer would be 150 ^-^

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3 years ago

5/2 times x = 1 solve for x

olya-2409 [2.1K]

Step-by-step explanation:

5/2 times x = 1

5/2 * x = 1

5x =2

x = 2/5

x = 0.4

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3 years ago

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15c² - 5c. Factorise completely

KATRIN_1 [288]

Looking at the problem, what we must do to complete this question is to completely factor the expression that was provided. The expression that was provided is $15c^2 - 5c$ .

The first step that we must do is to take a look at the expression and see what the two pieces of the expression have in common. We can see that both $15c^2$ and $-5c$ have the number 5 and the variable c associated with them so we can factor out those two.

<u>Factor out 5c</u>

$15c^2 - 5c$

$5c(\frac{15c^2}{5c}) - 5c(\frac{5c}{5c})$

$5c(3c) - 5c(1)$

$5c(3c - 1)$

Now we have completely factored out the expression that was provided in the problem statement and we came to final answer of $5c(3c - 1)$ .

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2 years ago

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