J(2x+9) m(6x-1)<br> i don’t get this at all

Pls help me ! i need help

Blizzard [7]

Answer:

what do you need help with?

7 0

3 years ago

Read 2 more answers

If sin(x) = M, with M > 0, find the value of then sin(x - pi) =

Alexus [3.1K]

Step-by-step explanation:

sin(x) = M, M > 0

= sin(x - π)

= sin(x)cos(π) - cos(x)sin(π)

= sin(x).(-1) - cos(x).0

= -sin(x) - 0

= -sin(x)

= -M

7 0

2 years ago

See the picture below

mart [117]

Answer:

a) 301.59 cubic centimeters

b) 235.87 square centimeters

Step-by-step explanation:

a)

Volume of ice cream cone is volume of hemisphere PLUS volume of cone.

Volume of Hemisphere = $\frac{\frac{4}{3}\pi r^3}{2}$

radius is given as 4, so,

Volume of Hemisphere = $\frac{\frac{4}{3}\pi r^3}{2}\\=\frac{\frac{4}{3}\pi (4)^3}{2}\\=134.04$

Now, Volume of Cone = $\frac{1}{3}\pi r^2 h$

Where radius is 4 and height is 10, so,

Volume of Cone = $\frac{1}{3}\pi r^2 h\\=\frac{1}{3}\pi (4)^2 (10)\\=167.55$

Volume of Ice Cream Cone = 134.04 + 167.55 = 301.59 cubic centimeters

b)

Surface area of ice cream cone is surface area of hemisphere PLUS surface area of cone.

Surface Area of Hemisphere = $2\pi r^2\\=2\pi (4)^2\\=100.53$

Surface Area of Cone = $\pi r^2+\pi rl$

We dont need to use the first part, $\pi r^2$ since it is "inside". We need to find l, slant height, by using pythagorean theorem on a triangle we can make (bottom right).

4^2 + 10^ 2 = l^2

16 + 100 = l^2

116 = l^2

l = 10.77

Now to find the surface area of cone = $\pi rl\\=\pi (4)(10.77)\\=135.34$

Surface area of ice cream cone = 100.53 + 135.34 = 235.87 square centimeters

5 0

3 years ago

An aquarium 2 m long, 1 m wide, and 1 m deep is full of water. Find the work needed to pump half of the water out of the aquariu

loris [4]

Answer:

Workdone = 2450Joules

Step-by-step explanation:

Let the top of the aquarium be at height 0.

Let the bottom of the aquarium be at height 1

F = mg = 2p◇x × g

F= 2000◇x × 9.8

F = 19600◇x

Workdone = 19600xdx

Total workdone = Integral (limits 0.5 -0)19600×dx

Total work = [9800x^2]^0.5

Total work= 9800× 0.5^2 = 2450 Joules

6 0

2 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago

J(2x+9) m(6x-1) i don’t get this at all