<span> For example, <span>x </span>> 6 or <span>x < </span>2. The solution to this compound inequality is all the values of <span>x </span>in which <span>x </span>is either greater than 6 or x is less than 2. You can show this graphically by putting the graphs of each inequality together on the same number line.</span>
The graph has an open circle on 6 and a blue arrow to the right and another open circle at 2 and a red arrow to the left. In fact, the only parts that are not a solution to this compound inequality are the points 2 and 6 and all the points in between these values on the number line. Everything else on the graph is a solution to this compound inequality.
<span>Let’s look at another example of an or compound inequality, x > 3 or x</span> <span>≤ </span>4. <span>The graph of </span>x<span> > 3 has an open circle on 3 and a blue arrow drawn to the right to contain all the numbers greater than 3.</span>
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Answer:
A. 15/32 of the writing utensils are black pens
Answer:
Given
Edge of a cube = 10cm
Length, l = 12.5 cm
Breadth, b = 10cm
Height, h = 8 cm
Find out
We have to find
i) Which box has the greater lateral surface area and by how much?
ii) Which box has the smaller total surface area and by how much?
Solution
(i)
Lateral surface area of a cube = 4 * (edge)2
= 4 * 102 cm2
= 400 cm2
Lateral surface area of a cuboid = 2 (lh + bh)
= 2 (12.5 * 8 + 10 * 8) cm2
= 2 (100 + 80) cm2
= 360 cm2
So, the lateral surface area of the cubical box is greater than cuboidal box by (400 cm2 – 360 cm2) which is 40 cm2.
(ii)
Total surface area of a cube = 6 * (edge)2
= 6 * 102 cm2
= 600 cm2
Total surface area of cuboid = 2 (lb + bh + lh)
= 2 (12.5 * 10 + 10 * 8 + 12.5 * 8) cm2
= 2 (125 + 80 + 100) cm2
= 610 cm2
Therefore, the total surface area of the cuboidal box is greater than the cubical box by (610 cm2 – 600 cm2) which is 10 cm2.
