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aksik [14]
3 years ago
10

What are the two types of compound inequalities? Give an example of each?

Mathematics
2 answers:
sveta [45]3 years ago
8 0
Hello There!

Two types of compound inequalities are:
A sentence with two inequalities joined by And.
A sentence with two inequalities joined by Or.

An example of one with And:
5x - 3 < 12 AND 4x + 1 > 25

An example of one with Or:
x - 5 > 0 OR 3x - 1 < 8.

Hope This Helps You!
Good Luck :) 

- Hannah ❤



cupoosta [38]3 years ago
4 0

<span> For example, <span>x </span>> 6 or <span>x < </span>2. The solution to this compound inequality is all the values of <span>x </span>in which <span>x </span>is either greater than 6 or x is less than 2. You can show this graphically by putting the graphs of each inequality together on the same number line.</span>

 

 

The graph has an open circle on 6 and a blue arrow to the right and another open circle at 2 and a red arrow to the left. In fact, the only parts that are not a solution to this compound inequality are the points 2 and 6 and all the points in between these values on the number line. Everything else on the graph is a solution to this compound inequality.

 

<span>Let’s look at another example of an or compound inequality, x > 3 or x</span> <span>≤ </span>4. <span>The graph of </span>x<span> > 3 has an open circle on 3 and a blue arrow drawn to the right to contain all the numbers greater than 3.</span>

 okay plz tell me if you need more help


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Eddi Din [679]

Answer:

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2 years ago
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Roman55 [17]
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7 0
3 years ago
The number of tickets purchased by an individual for Beckham College's holiday music festival is a uniformly distributed random
Zanzabum

1) Mean: 6.5

2) Standard deviation: 3.2

Step-by-step explanation:

1)

A uniform random distribution is the distribution of a variable that can assume n different values, and each of these values is equally likely to occur.

This means that the probability of occurring of each of these values is the same:

p(x_1)=p(x_2)=...=p(x_n)

For a uniform random distribution, the mean of the distribution is simply equal to the median value of the distribution, which is exactly at the center of the distribution itself. It can be calculated as

\bar x = \frac{1}{2}(a+b)

where

a is the lowest value of the distribution

b is the highest value of the distribution

Here the distribution consists of all values ranging from 1 to 12, so:

a = 1

b = 12

Therefore the mean value is

\bar x=\frac{1}{2}(1+12)=6.5

2)

For a uniform random distribution, it can be dimostrated that the variance of the distribution is

\sigma^2 = \frac{1}{12}(b-a)^2

For the distribution in this problem, we have:

a = 1

b = 12

Therefore the variance is

\sigma^2 = \frac{1}{12}(12-1)^2=10.08

The standard deviation is the square root of the variance, therefore for this distribution it is:

\sqrt{\sigma^2}=\sqrt{10.08}=3.2

Learn more about mean and standard deviation:

brainly.com/question/6073431

brainly.com/question/8799684

brainly.com/question/4625002

#LearnwithBrainly

3 0
3 years ago
Please help and explain with these 2 math questions!!!!!!
Volgvan

1)  -10x+y=4

Now, you should substitute x in every situation.

* x=-2 <em>=> -10*(-2)+y=4... 20+y=4... <u>y=-16</u></em>

<em />* x=-1 =>-10*(-1)+y=4... 10+y=4... <u>y=-6</u>

<u />*x=0 => -10*0+y=4... <u>y=4</u>

<u />* x=1 =>  -10*1+y=4... -10+y=4... <u>y=14</u>

<u />* x=2 => -10*2+y=4... -20+y=4... <u>y=24</u>

<u>2)</u> -5x-1=y

For example: x=0

-5*0-1=-1

<u>
</u>



6 0
3 years ago
Find the sum or difference.<br>81-3<br>3​
yuradex [85]

Answer:

48

Step-by-step explanation:

81 - 33 = 48

8 0
3 years ago
Read 2 more answers
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