What are the two types of compound inequalities? Give an example of each?

2 answers:

8 0

Hello There!

Two types of compound inequalities are:
A sentence with two inequalities joined by And.
A sentence with two inequalities joined by Or.

An example of one with And:
5x - 3 < 12 AND 4x + 1 > 25

An example of one with Or:
x - 5 > 0 OR 3x - 1 < 8.

Hope This Helps You!
Good Luck :)

- Hannah ❤

cupoosta [38]3 years ago

4 0

For example, x > 6 or x < 2. The solution to this compound inequality is all the values of x in which x is either greater than 6 or x is less than 2. You can show this graphically by putting the graphs of each inequality together on the same number line.

The graph has an open circle on 6 and a blue arrow to the right and another open circle at 2 and a red arrow to the left. In fact, the only parts that are not a solution to this compound inequality are the points 2 and 6 and all the points in between these values on the number line. Everything else on the graph is a solution to this compound inequality.

Let’s look at another example of an or compound inequality, x > 3 or x ≤ 4. The graph of x > 3 has an open circle on 3 and a blue arrow drawn to the right to contain all the numbers greater than 3.

okay plz tell me if you need more help

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Find the value of angle x , angle y, and angle z in figure.

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$\bf \underline{★ Solution-} \\$

In the given figure, we are given with two lines which are parallel to each other. We are also given with two lines which forms a triangle and also forms as a transversal lines to the parallel lines. We are also given that the given triangle is an isosceles triangle. So, we can say that the other angle in the triangle also measures 75°.

Now, let's find the value of the ∠x.

We know that the alternate angles in the parallel line always measures the same as the one which is in it's alternate side. So,

$\sf \leadsto \angle{x} = {75}^{\circ}$

Now, let's find the value of the ∠z.

We know that, all the angles in a triangle always adds up to 180°. In the given triangle, we are given with two angles, so we can easily find the third angle.

$\sf \leadsto {75}^{\circ} + {75}^{\circ} + \angle{z} = {180}^{\circ}$

$\sf \leadsto {150}^{\circ} + \angle{z} = {180}^{\circ}$

$\sf \leadsto \angle{z} = 180 - 150$

$\sf \leadsto \angle{z} = {30}^{\circ}$

Now, let's find the value of the ∠y.

We know that all the angles that forms a straight line always equals up to 180° (or) the the straight line angle always measures 180°. So, we can find the value of the ∠y by this concept.

$\sf \leadsto {75}^{\circ} + {30}^{\circ} + \angle{y} = {180}^{\circ}$