What are the two types of compound inequalities? Give an example of each?

2 answers:

8 0

Hello There!

Two types of compound inequalities are:
A sentence with two inequalities joined by And.
A sentence with two inequalities joined by Or.

An example of one with And:
5x - 3 < 12 AND 4x + 1 > 25

An example of one with Or:
x - 5 > 0 OR 3x - 1 < 8.

Hope This Helps You!
Good Luck :)

- Hannah ❤

cupoosta [38]3 years ago

4 0

For example, x > 6 or x < 2. The solution to this compound inequality is all the values of x in which x is either greater than 6 or x is less than 2. You can show this graphically by putting the graphs of each inequality together on the same number line.

The graph has an open circle on 6 and a blue arrow to the right and another open circle at 2 and a red arrow to the left. In fact, the only parts that are not a solution to this compound inequality are the points 2 and 6 and all the points in between these values on the number line. Everything else on the graph is a solution to this compound inequality.

Let’s look at another example of an or compound inequality, x > 3 or x ≤ 4. The graph of x > 3 has an open circle on 3 and a blue arrow drawn to the right to contain all the numbers greater than 3.

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HELPPPPPP pls give explaiantikn or work pls pls pls pls brainliest

Andru [333]

Answer:

Elizabeth had 30 stamps originally.

Step-by-step explanation:

Let,

x be the number of stamps Elizabeth have.

Number of stamps given to John = 1/6 of x = $\frac{1}{6}x$

Remaining stamps = $x-\frac{1}{6}x = \frac{6x-1x}{6} = \frac{5}{6}x$

Stamps given to Peter = 1/5 of remainder = $\frac{1}{5}*\frac{5}{6}x = \frac{1}{6}x$

Number of stamps left = 20

Now,

$\frac{1}{6}x + \frac{1}{6}x + 20 = x\\\\\frac{1x+1x+120}{6} = x\\\\\frac{2x+120}{6} = x\\\\2x + 120 = 6x \\\\120 = 6x - 2x \\\\120 = 4x \\4x = 120$

Dividing both sides by 4

$\frac{4x}{4}=\frac{120}{4}\\x=30$

Hence,

Elizabeth had 30 stamps originally.

3 0

3 years ago

Write an equation for the line given that m=0 and the y intercept is (0,-2)

AfilCa [17]

Answer:

$\boxed{y=-2}$

Step-by-step explanation:

$The \ graph \ of \ the \ equation: \\ \\ y=mx+b \\ \\ is \ a \ line \ whose \ slope \ is \ m \ and \ whose \ y-intercept \ is \ (0, b)$

In this problem, this line has a slope $m=0$ , that is, this is an horizontal straight line. The intercept is the point $(0,-2)$ , so $b=-2$ . Finally, by substituting these values we have: