You could use the information from part A to get B. I'm not sure if you want A or not, so I'll do it as well.
A
Eo = 10^4.4 Joules
E = 2 * 10^15
Formula
M = (2/3) log (E/Eo)
M = 2/3 * log (2 * 10^15/10^(4.4) )
M = 2/3 * log( 7.9621* 10^10)
M = 2/3 * 10.901
M = 7.26735 on the Richter scale. That is a huge amount of energy.
Part B
Suppose that you use Eo and your base. Eo is 10^4.4
Now the new earthquake is E = 10000 * Eo
So what you get now is M = (2/3)* Log(10000 * Eo / Eo )
The Eo's cancel out.
M = 2/3 * log(10000)
M = 2/3 of 4
M = 8/3
M = 2.6667 difference in the Richter Scale Reading. It is still an awful lot of energy.
What this tells you is that if the original reading was (say) 6 then the 10000 times bigger reading would 8.266667
Answer: M = 2.6667
1/6 bc they all have an equal chance to be all the numbers on the die and their is only 6 numbers on the die so you have 1:6 probability of it being 3
6 feet:10 hours
multiply by 1.5 on both sides
9 feet:15 hours
answer: 9 ft
A) 8 - add up the how many numbers there are after the 4 on the left column
b) 41 - line up all of the numbers from least to greatest and find the middle number
c) 39 - do step b again but this time remove the oldest worker and add the younger one in
Answer:
- 7, - 3, 1, 5
Step-by-step explanation:
Using the recursive rule and a₁ = - 7, then
a₂ = a₁ + 4 = - 7 + 4 = - 3
a₃ = a₂ + 4 = - 3 + 4 = 1
a₄ = a₃ + 4 = 1 + 4 = 5
The first four terms are - 7, - 3, 1, 5
