1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
damaskus [11]
4 years ago
8

Select the correct answer. Find the inverse of function f. f(x) = 1/2x + 7

Mathematics
1 answer:
timofeeve [1]4 years ago
7 0

Answer:

f'(x)= 2x - 14

Step-by-step explanation:

change f(x) to y   y = 1/2x + 7

switch x and y    x = 1/2y + 7

multiply everything by 2 to cancel the denominator 2x = y + 14

solve for y     2x - 14 = y

then change y to f'(x)   f'(x) = 2x - 14

You might be interested in
Please help this is due in 10 minutes!
Reptile [31]

Answer:

The answer is 16÷1/10

Step-by-step explanation:

That equals 160ft

7 0
3 years ago
Divide 30 charms into two equal groups so that ratio is 2 to 3. How many to put in each group?
Vera_Pavlovna [14]

Answer:

12 & 18

Explanation:

My Asian friend Ryen, actually just told me answer,so there you go.

Or, 6x2=12

and 6x3=18

That works too

4 0
3 years ago
Read 2 more answers
(a) A survey of the adults in a town shows that 8% have liver problems. Of these, it is also found that 25% are heavy drinkers,
grandymaker [24]

Answer:

i. Has a liver problems?

= 0.08

ii. Is a heavy drinker ?

= 0.066

iii. If a person is found to be a heavy drinker, what is the probability that this person has liver problem?

= 0.303

iv. If a person is found to have liver problems, what is the probability that this person is a heavy drinker?

= 0.25

v. If a person is found to be a non –drinker, what is the probability that this person has liver problems?

= 0.104

Step-by-step explanation:

We have 2 Events in this question

Event A: People with liver problems

Event B : People without liver problems

Event A: People with liver problems

Let us represent people with liver problems as = (L)

a)8% have liver problems. = P(L)

Under liver problems we have:

b) 25% are heavy drinkers = P( L & H)

c) 35% are social drinkers = P( L & S)

d) 40% are non-drinkers. = P( L & N)

Event B( no liver problem)

Let us represent no liver problem as NL

We are not given in the question but Probability of having no liver problem = 100 - Probability of having liver problem

= 100 - 8% = 92 %

P(NL ) = 92%

From the question, For people without liver problems, we have:

a) 5% are heavy drinkers = P(NL & H)

b) 65% are social drinkers = P( NL & S)

c) 30% do not drink at all = P( NL & N)

An adult is chosen at random, what is the probability that this person

i. Has a liver problems?

P(L) = 8% or 0.08

ii. Is a heavy drinker ?

From the question, we have:

Probability of people that have liver problems and are heavy drinkers P(L & H) = 25% = 0.25

Probability of people that have do not have liver problems and are heavy drinkers P(NL & H) = 5% = 0.05

Probability ( Heavy drinker) =

P(L) × P(L & H) + P(NL) × P(NL & H)

= 0.25 × 0.08 + 0.05 × 0.92

= 0.066

iii. If a person is found to be a heavy drinker, what is the probability that this person has liver problem?

Probability (Heavy drinker and has liver problem) = [P(L) × P(L & H)] ÷ [P(L) × P(L & H)] + [P(NL) × P(NL & H) ]

= [0.25 × 0.08] ÷ [0.25 × 0.08] + [0.05 × 0.92]

= 0.303030303

Approximately = 0.303

iv. If a person is found to have liver problems, what is the probability that this person is a heavy drinker?

P(L & H) = 25% = 0.25

v. If a person is found to be a non –drinker, what is the probability that this person has liver problems.?

People with liver problems are non-drinkers. = P( L & N) = 40% = 0.4

People without liver problems and do not drink at all = P( NL & N) = 30% = 0.3

Probability (non drinker and has liver problem) = [P( L & N) × P(L & H)] ÷ [P( L & N) × P(L & H)] + [ P( NL & N) × P(NL & H) ]

= [0.4× 0.08] ÷ [0.4 × 0.08] + [0.3 × 0.92]

= 0.1038961039

Approximately ≈ 0.104

5 0
3 years ago
A basketball team played six games and those games the team won by seven points lost by 20 one by eight one by 11 lost by 3 and
natima [27]

Answer: 2

Step-by-step explanation 7 - 20 + 8 + 11 - 3 + 9 = 12 divided by 6 because there are 6 numbers equals 2

7 0
3 years ago
Let f = {(–2, 4), (–1, 2), (0, 0), (1, –2), (2, –5)}. Let g = {(–3, 3), (–1, 1), (0, –3), (1, –4), (3, –6)}. What is g(f(2))? -5
Andreyy89
First find the value of f(2). This is the y coordinate of the point with x = 2 as the x coordinate. Look through the set f and see that (2,-5) is one of the points. This point says x = 2 and y = -5. So f(2) = -5

We will replace the f(2) with -5 to go from this
g(f(2))
to this
g(-5)

Now repeat the same steps but for g this time
Look through the set g for a point with x coordinate of -5. That point is NOT listed. Why not? Because the x values are -3, -1, 0, 1 and 3. None of which are -5.
No such point exists.

Final Answer: The composition is undefined
6 0
4 years ago
Read 2 more answers
Other questions:
  • S explain how the values of the numbers 350 and 3500 are different
    10·1 answer
  • Maria finds a local gym that advertises 102 training sessions for $767. Find the cost of 117 training sessions.
    5·1 answer
  • Drag each tile to the correct box. Arrange the complex numbers in order according to the quadrant in which they appear, starting
    14·1 answer
  • 96 pencils come in bx if 4 teachers share 3 boxes how many each teacher receive show your work
    14·2 answers
  • Could someone help me?
    9·1 answer
  • Evaluate z + z + z for x = 2, y = -3, z = -4.<br><br> 12<br> -12<br> -9<br> -6<br><br> Need help!!
    15·1 answer
  • Find decimal notation. <br> 0.6%=
    12·2 answers
  • A woman is floating in a boat that is 175 feet from the base of a cliff. The cliff is 250 feet tall. What is the angle of elevat
    8·1 answer
  • Find the product of (5a^3b) (2ab)
    11·1 answer
  • If a(x) = 3x + 1 and b (x) = StartRoot x minus 4 EndRoot, what is the domain of (b circle a) (x)?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!