Question

1. Dole Pineapple Inc. is concerned that the 16-ounce can of sliced pineapple is being overfilled. Assume the standard deviation of the process (population) is .03 ounces. The quality control department took a random sample of 50 cans and found that the arithmetic mean weight was 16.05 ounces. At the 5 percent level of significance, can we conclude that the mean weight is greater than 16 ounces?

Answer 1

Answer:

Claim : The mean weight is greater than 16 ounces

$H_0:\mu = 16 \\H_a:\mu >16$

x = 16.05

n = 50

$\sigma = 0.03$

Since n > 30 and population standard deviation is given

So, we will use z test

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

Substitute the values

$z=\frac{16.05-16}{\frac{0.03}{\sqrt{50}}}$

$z=11.7851$

Critical value at 0.05 significance level is 1.645

z statistic > critical value

So, we reject the null hypothesis

So, we can conclude that the mean weight is greater than 16 ounces .