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rusak2 [61]
3 years ago
12

Write an equation of the line passing through the point A(6,−1)A(6,−1) that is perpendicular to the line y = −2x+8y = −2x+8.

Mathematics
1 answer:
Olegator [25]3 years ago
3 0
So the equation has to pass through (6,-1) and be perpendicular to y = -2x + 8.
The slope is -2, and to get the slope of a line perpendicular to another line you have to find the negative reciprocal of that slope. That means -2 is equal to 
-2/1, and if you flip those numbers and find the opposite of that number making it positive, the slope of a line perpendicular to it is 1/2.
But the line also has to pass through (6,-1), so we have to find the y-intercept of the new line.
To do that, you multiply 6(the x) by the 1/2(the slope) and get 3. Then you subtract 3(previous answer) from -1(the y) and get -4. That means the y-intercept is -4!
All that's left is to build the equation with this information. The equation is: 
y = -4 + 1/2x 
Hope this helps!
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C=10,000-110x+0.45x^2
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7 0
3 years ago
5x^4x-2 what's result ​
pashok25 [27]

Answer:

There is no result.

Step-by-step explanation:

This question does not have an answer, as you would need to plug in an x value to get any sort of answer.

3 0
2 years ago
a local school has a gymnasium that is 48ft long, 36ft wide with an 18ft high ceiling. the school maintenance staff is painting
pshichka [43]

Answer:

8

Step-by-step explanation:

Let's first measure the four walls.  We'll have 2 walls 48 ft wide x 18 ft high (the longer walls), then 2 walls 36 ft x 18 ft high.

These are rectangles we can easily calculate the area:

longer walls: 2 (48 * 18) = 2 * 864 = 1,728 sq ft

shorter walls: 2 (36 x 18) = 2 * 648 = 1,296 sq ft

Total of the walls: 1,728 + 1,296  = 3,024 sq ft.

Now, we assume they'll paint everything and that there are no windows.

Each can covers 400 sq ft.

If we divide 3,024 by 400 we get 7.56

So, they'll need to buy 8 cans of paint to do the job.  In such problems, we always round up, otherwise they wouldn't have enough paint.

8 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each equation with the operation yo
Tanzania [10]

The quadratic equations and their solutions are;

9 ± √33 /4 = 2x² - 9x + 6.

4 ± √6 /2 = 2x² - 8x + 5.

9 ± √89 /4 = 2x² - 9x - 1.

4 ± √22 /2 = 2x² - 8x - 3.

Explanation:

Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.

We have to solve all of the five equations to be able to match the equations with their solutions.

2x² - 8x + 5, here a = 2, b = -8, c = 5.                                                  x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(5) / 2(2) = 8 ± √64 - 40/4.     24 can also be written as 4 × 6 and √4 = 2. So                                                                                     x = 8 ± 2√6 / 2×2= 4±√6/2.

2x² - 10x + 3, here a = 2, b = -10, c = 3.                                                   x =-b ± √b² - 4ac / 2a =-(-10) ± √(-10)² - 4(2)(3) / 2(4) = 10 ± √100 + 24/4. 124 can also be written as 4 × 31 and √4 = 2. So                                                                              x = 10 ± 2√31 / 2×2 = 5 ± √31 /2.

2x² - 8x - 3, here a = 2, b = -8, c = -3.                                                    x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4.     88 can also be written as 4 × 22 and √4 = 2. So                                                                             x = 8 ± 2√22 / 2×2 = 4± √22/2.

2x² - 9x - 1, here a = 2, b = -9, c = -1.                                                     x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4.                                          x = 9 ± √89 / 4.

2x² - 9x + 6, here a = 2, b = -9, c = 6.                                                    x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(6) / 2(2) = 9 ± √81 - 48/4.                                                                             x = 9 ± √33 / 4

To match we solve the monomials.

1. -15u^3 + 5u^3

Adding

-15u^3 + 5u^3=-10u^3

2.  10u^3 +(-5u^3)

Adding

10u^3-5u^3=5u^3

3. 10u^3 + 5u^3

Adding

10u^3 + 5u^3=15u^3

4.  5u^3+ (-10u^3)

Adding

5u^3-10u^3 =-5u^3

Two separate ways to find the answers.

7 0
2 years ago
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Step-by-step explanation:

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