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FinnZ [79.3K]
2 years ago
6

Julian spends 85 min on HW each day. If 20% of the time is spent on math HW, how many minutes a day is Julian spending on math H

W?
Mathematics
2 answers:
allsm [11]2 years ago
7 0
The answer is 17 minutes
Kamila [148]2 years ago
3 0
20/100=x/85
Cross multiply
(20)(85)=100x
1700=100x
Divide by 100
X = 17 minutes
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HEPL MEE, I NEED EXTREME HELP!
natta225 [31]

Answer:

A= ( 5 x 3 ) x [(9-5)x3 divided by 2]

15+6

=21

P= 5+5+3+9

=22

6 0
2 years ago
The surface area of this rectangular prism is 14,664 square yards. What is the value of z?
worty [1.4K]
The value of z is 13,184 because you first multiply 37 times 40 and you get 1,480 , so then you subtract the area which is 14,664 minus 1,480 and the answer you get is z
6 0
3 years ago
what is the distance between the points (4, 5) and (10, 13) on a coordinte plane a. 12 units b. 8 units c. 10 units d. 14 units
qaws [65]

Answer:

<h2>10 units</h2>

Option C is the correct option

Step-by-step explanation:

Let the points be A and B

A ( 4 , 5 ) ------> ( x1 , y1 )

B ( 10 , 13 ) ------> ( x2 , y2 )

Now, let's find the distance between these points:

\sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} }

plug the values

= \:  \sqrt{(10 - 4) ^{2} +  {(13 - 5)}^{2}  }

Calculate the difference

=  \sqrt{ {(6)}^{2} +  {(8)}^{2}  }

Evaluate the power

=  \sqrt{36 + 64}

Add the numbers

=  \sqrt{100}

Write the number in exponential form with. base of 10

=  \sqrt{ {(10)}^{2} }

Reduce the index of the radical and exponent with 2

= 10 \: units

Hope this helps..

Best regards!!

7 0
2 years ago
You invested $1,200 in a mutual fund. Your account now has a value of $1,333. what was your gain?
OleMash [197]
You have invested 1200 dollars in your mutual fund and now gained 1333 dollars. First let's solve how much money added to your investment.
=> 1333 - 1200 = 133 dollars was added to your account
=> 133 / 1200 = 0.11 
Next, lets convert this to decimal value.
=> 0.11 * 100% = 11% was added to you investment.
7 0
3 years ago
Read 2 more answers
Cos s=-2/5 and sin t=4/5, s and t are in quadrant II<br> find cos(s+t) and cos(s-t)
mojhsa [17]

Answer:

•cos(s+t) = cos(s)cos(t) - sin(s)sin(t) = (-⅖).(-⅗) - (√21 /5).(⅘) = +6/25 - 4√21 /25 = (6-4√21)/25

•cos(s-t) = cos(s)cos(t) + sin(s)sin(t) = (-⅖).(-⅗) + (√21 /5).(⅘) = +6/25 + 4√21 /25 = (6+4√21)/25

cos(t) = ±√(1 - sin²(t)) → -√(1 - sin²(t)) = -√(1 - (⅘)²) = -⅗

sin(s) = ±√(1 - cos²(s)) → +√(1- cos²(s)) = +√(1 - (-⅖)²) = √21 /5

5 0
3 years ago
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