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zhuklara [117]
2 years ago
9

Michelle records the value of one euro in U.S dollars each day for her social studies project.

Mathematics
1 answer:
natka813 [3]2 years ago
3 0

Answer:

On Monday the value was 1.448, Tuesday it was 1.443, Wednesday it was 1.452, and Thursday it was 1.458.

Step-by-step explanation:

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Write the equation of the line that is perpendicular to the line 5y=x−5 through the point (-1,0).
Artemon [7]

Hey there!

First, we want to put the equation of this first line in slope-intercept form.

5y=x-5

We divide both sides by 5.

y=1/5x-1.

The slope of a perpendicular is line is the negative reciprocal of the slope of the original line. The slope of a line perpendicular to a line with the equation y=1/2x would be -2, because you flip the numerator and denominator and then make it negative.

So, this means that the slope of the line perpendicular to the line y=1/5x-1 is -5. So, here's our equation so far.

y= -5x+b

Now, we need to find the b. To do this, we can plug in this point (-1,0) that this perpendicular line goes through and solve for b.

0=-5(-1)+b

0=5+b

b= -5

So, this gives us the equation y= -5x-5

Have a wonderful day!

7 0
3 years ago
Taye recruits two people to be election campaign volunteers. The next week he ask each of those volunteers to recruit two more c
jeka94

Using a geometric sequence, it is found that:

a) For the first 5 weeks, the numbers are: 2, 4, 8, 16, 32

b) Hence some of the volunteers can stop recruiting new volunteers during the 7th week.

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

a_n = a_1q^{n-1}

In which a_1 is the first term.

For this problem, on the first week there are 2 people, and since each new people involve two more, the common ratio is of 2, hence the parameters for the geometric sequence are:

a_1 = 2, q = 2

Hence the number of people after n weeks is:

a_n = 2 \times 2^{n - 1}

For the first 5 weeks, the numbers are:

  • a_1 = 2 \times 2^{1 - 1} = 2
  • a_2 = 2 \times 2^{2 - 1} = 4
  • a_3 = 2 \times 2^{3 - 1} = 8
  • a_4 = 2 \times 2^{4 - 1} = 16
  • a_5 = 2 \times 2^{5 - 1} = 32

There will be 150 volunteers when a_n = 150, hence:

2 \times 2^{n - 1} = 150

2^{n-1} = 75

\frac{2^n}{2} = 75

2^n = 150

n = 7...

The above is because 2^7 = 128 and 2^8 = 256, and 128 < 150 < 256.

Hence some of the volunteers can stop recruiting new volunteers during the 7th week.

More can be learned about geometric sequences at brainly.com/question/11847927

#SPJ1

3 0
1 year ago
If two lines intersect, they intersect at a ____.
V125BC [204]
The answer is the word “point”. Hope this helps.
3 0
2 years ago
Read 2 more answers
What is 2160 minus 1600 long way
lilavasa [31]
Hey there, Lets solve this problem together. 

The First step is to line up the numbers. 

=  2160&#10;&#10;- 1600 

\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left} 

<span>We calculate </span>0-0<span>the result of which is </span>0<span> 
</span>
<span>We calculate </span>6-0<span> the result of which is </span>6<span>.
</span>
Since we get a negative number in the next column, we must take 1 from the next column and carry it over to this column. Now the number will be changed to 10.

We calculate 10+1-6, and the result is 5. 

<span>We calculate </span>2-1-1<span> the result of which is</span>0<span>. 
</span>
Therefore, 

2160 - 1600 = 0560 
8 0
2 years ago
To find the product of 42.12 and 10³, move the decimal point in 42.12 __ places to the right because 10³ has __ zeros.
docker41 [41]

Answer:

Both answers are 3.

Step-by-step explanation:

10^3 = 10 * 10 * 10 = 1000

When you multiply 42.12 by 10^3, you are multiplying 42.12 by 1000.

When you multiply a number by a power of 10, such as 10, 100, 1000, etc., move the decimal point of the number to the right the same number of places as the number of zeros in the power of 10.

42.12 * 1000 = 42,120

5 0
3 years ago
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