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3 years ago

7

Please help me with this!

1 answer:

mafiozo [28]3 years ago

4 0

A (-5, 6)
B (-5, 2)
C (-9, 2)
D (-9, 6)

As it is just a rotation around the origin by 180, you can just change the sign in front of the numbers :)

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Let logbA=5;logbC=7;logbD=2 what is the value of logb(A^5C^2/D^6)

Alisiya [41]

Answer:

<h2>A. 27</h2>

Step-by-step explanation:

$\text{De}\text{finition of logarithm}\ \log_ab=c\iff a^c=b.\\\\\log_bA=5\iff A=b^5\\\\\log_bC=7\iff C=b^7\\\\\log_bD=2\iff D=b^2\\\\\dfrac{A^5C^2}{D^6}=\dfrac{(b^5)^5(b^7)^2}{(b^2)^6}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\dfrac{b^{25}b^{14}}{b^{12}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\ \text{and}\ \dfrac{a^m}{a^n}=a^{m-n}\\\\=b^{25+14-12}=b^{27}\\\Downarrow\\\\\log_b\left(\dfrac{A^5C^2}{D^6}\right)=\log_bb^{27}\qquad\text{use}\ \log_aa^n=n\\\\\log_b\left(\dfrac{A^5C^2}{D^6}\right)=27$

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3 years ago

Find the circumference of the object. Use 3.14 or 22/7

dmitriy555 [2]

C=2pi r
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3 years ago

50 divided 2 equals what

Grace [21]

It equals 25
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4 years ago

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Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$

Viefleur [7K]

QUESTION 1

Given that:

$f(x)=2x^2+3x-9$ ,

$g(x)=5x+11$ ,

and

$h(x)=-3x^2+1$

Then;

$f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)$

$f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1$

Group similar terms;

$f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1$

Simplify;

$f(x)-g(x)+h(x)=-x^2-2x-19$

QUESTION 2

Given that;

$f(x)=4x-7$ .

$g(x)=(x+1)^2$

and

$s(x)=f(x)+g(x)$

Substitute the functions;

$s(x)=4x-7+(x+1)^2$

Substitute x=3

$s(3)=4(3)-7+(3+1)^2$

$s(3)=12-7+(4)^2$

$s(3)=5+16$

$s(3)=21$

QUESTION 3

Given:

$f(x)=3x+2$

$g(x)=x^2-5x-1$

$f(g(x))=f(x^2-5x-1)$

This implies that;

$f(g(x))=3(x^2-5x-1)+2$

Expand the parenthesis;

$f(g(x))=3x^2-15x-3+2$

$f(g(x))=3x^2-15x-1$

QUESTION 4

The given function is;

$f(x)=3(x-6)^2+1$

Let

$y=3(x-6)^2+1$

$\Rightarrow y-1=3(x-6)^2$

$\Rightarrow \frac{y-1}{3}=(x-6)^2$

$\Rightarrow \sqrt{\frac{y-1}{3}}=x-6$

$\Rightarrow x=6+\sqrt{\frac{y-1}{3}}$

The range is:

$\frac{y-1}{3}\ge0$

$y-1\ge0$

$y\ge1$

The interval notation is;

$[1,+\infty)$

6 0

4 years ago

Please answer first then explain

Damm [24]

Answer:

B

1.25 each , times count B equals total C

8 0

3 years ago

Read 2 more answers