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kipiarov [429]
3 years ago
5

What is the Lcm of 2 and 7

Mathematics
1 answer:
wel3 years ago
5 0

Answer:

14

Step-by-step explanation:

The least common multiple is a number that both numbers can multiply something to get to, and the smallest possible common one.

Let's try listing out the multiples of 2:

2, 4, 6, 8, 10, 12, 14, 16, 18, 20

And the multiples of 7:

7, 14, 21, 28, 35, 42, 49, 56, 63, 70

Notice that both have the number 14 in common, and it is the first number that they do so.  There are lots of other multiples that they have in common too, but 14 is the least.

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I need help with those questions please help me.
Goshia [24]

Answer:

1 = 21 m

2 = 120 cm

3 = 84 cm

4 = 3 km

5 = 10 m

6 = 55 mm

7 = 60 cm

8 = 500 mm

Step-by-step explanation: you see where it says "perimeter = 3s" right? for each question you have to replace "s" with the number given so for the first one it would be 3 x 7. You had to do the same thing with the others but sometimes we get confused in math :D

8 0
2 years ago
Factoring Polynomials: 6-13a+6a^2
Firlakuza [10]
(Factor by grouping 2-3a)(3-2a)
6 0
3 years ago
A company's profit (in millions of dollars) can be represented by x^2-6x+12, where x is the number of years since the company st
Sergeu [11.5K]
The function that models the profit of the company in million of dollars is:

P= x^{2} -6x+12

where x represents the number of years since the company started. We want to find when the profit of the company was $4 million. Setting P as 4 in above equation, we can find the value of x when the profit was $4 million.

4= x^{2} -6x+12 \\  \\ 
 x^{2} -6x+8=0 \\  \\ 
 x^{2} -2x-4x+8=0 \\  \\ 
x(x-2)-4(x-2)=0 \\  \\ 
(x-2)(x-4)=0 \\  \\ 
x=2, x=4

Thus, we can conclude that the profit of the company was $4 million in 2nd and 4th year
6 0
3 years ago
Pls solve! Show work! If you give an explanation or show work I will mark brainliest!
SSSSS [86.1K]
Y = 9x
y = 5x + 24

9x = 5x + 24
9x - 5x = 24
4x = 24
x = 24/4
x = 6

y = 9x
y = 9(6)
y = 54

solution (6,54)....x = 6 and y = 54
8 0
3 years ago
Read 2 more answers
Based on an indication that mean daily car rental rates may be higher for Boston than for Dallas, a survey of eight car rental c
Elina [12.6K]

Answer:

t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058

The degrees of freedom are:

df=8+9-2=15

And the p value would be:

p_v =P(t_{15}>2.058) =0.0287

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are significantly higher than those in Dallas

Step-by-step explanation:

Data given

n_1 =8 represent the sample size for group Boston

n_2 =9 represent the sample size for group Dallas

\bar X_1 =47 represent the sample mean for the group Boston

\bar X_2 =44 represent the sample mean for the group Dallas

s_1=3 represent the sample standard deviation for group Boston

s_2=3 represent the sample standard deviation for group Dallas

We can assume that we have independent samples from two normal distributions with equal variances and that is:

\sigma^2_1 =\sigma^2_2 =\sigma^2

Let the subindex 1 for Boston and 2 for Dallas we want to check the following hypothesis:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

The statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

Where t follows a t student distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

Replacing we got:

\S^2_p =\frac{(8-1)(3)^2 +(9 -1)(3)^2}{8 +9 -2}=9

And the deviation would be just the square root of the variance:

S_p=3

The statitsic would be:

t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058

The degrees of freedom are:

df=8+9-2=15

And the p value would be:

p_v =P(t_{15}>2.058) =0.0287

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are significantly higher than those in Dallas

5 0
4 years ago
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