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3 years ago

What is the Lcm of 2 and 7

Mathematics

1 answer:

wel3 years ago

5 0

Answer:

Step-by-step explanation:

The least common multiple is a number that both numbers can multiply something to get to, and the smallest possible common one.

Let's try listing out the multiples of 2:

2, 4, 6, 8, 10, 12, 14, 16, 18, 20

And the multiples of 7:

7, 14, 21, 28, 35, 42, 49, 56, 63, 70

Notice that both have the number 14 in common, and it is the first number that they do so. There are lots of other multiples that they have in common too, but 14 is the least.

You might be interested in

Three consecutive integers have a sum of 87. Find the integers.

ozzi

Answer:

28, 29, 30

Step-by-step explanation:

<u>Let the integers be x- 1, x and x +1, then:</u>

x - 1 + x + x + 1 = 87
3x = 87
x = 29

The integers are 28, 29, 30

8 0

3 years ago

Read 2 more answers

In a function, y varies inversely with x. The consistent of variation is 4. Which table could represent the function?

lianna [129]

Answer:

none of the tables shown

Step-by-step explanation:

Inverse variation is

xy = k where k is the constant

xy = 4

in the top table

-2*2 = -4 so it cannot be the first table

In the middle table

-2 * -8 = 16 so it is not the middle table

In the bottom table

-2 *4 = -8 so it is not the bottom table

There must be a table not shown

5 0

3 years ago

Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

6 0

4 years ago

Read 2 more answers

The angles in a triangle are in the ratio 1:2:3. Show that the triangle is a right - angled triangle.

Alja [10]

Answer:

Angles in a triangles add up to 180°

Respectively 1 : 2 : 3 is going to be 1 x , 2 x and 3 x so,

1 x + 2 x + 3 x = 180°

⇒ Simplify

6 x = 180°

⇒ Divide by 6 on both sides to isolate x

x = 30°

Since the ratio was 1 x : 2 x : 3 x and x is 30°,

30 : 60 : 90

And since there is a 90° angle, it is a right - angled triangle

4 0

3 years ago

Which equation can be simplified to find the inverse of y = 5x2 + 10?

zmey [24]

f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10

Step-by-step explanation:

interchanging the variables

x = 5y^2 + 10

5y^2 +10 = x

5y^2 = x - 10

dividing by 5

5y^2/5 = x/5 + -10/5

y^2 = x/5 + - 10/5

y^2 = x/5 - 2

y = 5 (x-10) 0/5 (sq.rt)

g(5x^2 + 10) = 5x/5

g(5x^2 + 10) = x

f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10

5 0

3 years ago

Read 2 more answers