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Karo-lina-s [1.5K]
3 years ago
9

Simplify 12 - (-8)*4 = ? A. 20 B. 44 C. 80 D. 16

Mathematics
2 answers:
malfutka [58]3 years ago
6 0
12-
(-8)*4
12-(-32)= 12+32
44
kirza4 [7]3 years ago
4 0
You will do multiplication first and you will get -32 now you do 12 - (-32) and get 47
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1 3/4 divided by 1/2-1 1/2 to the 3rd
Marina CMI [18]

Answer:

-7/4

1/8

Step-by-step explanation:

1. If the problem is; (1 3/4) / (1/2 - 1 1/2)^(3)

<u>(a). Convert to improper fractions;</u>

(7/4) / (1/2 - 3/2)^3

<u>(b). Simplify;</u>

(7/4) / (-2/2)^3

(7/4) / (-1)^3

(7/4) / (-1)

-7/4

2. If the problem is; ((1 3/4) / (1/2)) - (1 1/2)^3

<u>(a). Convert to improper fractions;</u>

((7/4)/ (1/2)) - (3/2)^3

<u>(b). Simplify;</u>

((7/4)/ (1/2)) - (3/2)^3

((7/4)*(2/1)) - (27/8)

(7/2) - (27/8)

(28/8) - (27/8)

1/8

6 0
3 years ago
Find the volume v of the described solid s. the base of s is an elliptical region with boundary curve 4x2 + 9y2 = 36. cross-sect
Tasya [4]
4x^2+9y^2=36\iff\dfrac{x^2}9+\dfrac{y^2}4=1

defines an ellipse centered at (0,0) with semi-major axis length 3 and semi-minor axis length 2. The semi-major axis lies on the x-axis. So if cross sections are taken perpendicular to the x-axis, any such triangular section will have a base that is determined by the vertical distance between the lower and upper halves of the ellipse. That is, any cross section taken at x=x_0 will have a base of length

\dfrac{x^2}9+\dfrac{y^2}4=1\implies y=\pm\dfrac23\sqrt{9-x^2}
\implies \text{base}=\dfrac23\sqrt{9-{x_0}^2}-\left(-\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac43\sqrt{9-{x_0}^2}

I've attached a graphic of what a sample section would look like.

Any such isosceles triangle will have a hypotenuse that occurs in a \sqrt2:1 ratio with either of the remaining legs. So if the hypotenuse is \dfrac43\sqrt{9-{x_0}^2}, then either leg will have length \dfrac4{3\sqrt2}\sqrt{9-{x_0}^2}.

Now the legs form a similar triangle with the height of the triangle, where the legs of the larger triangle section are the hypotenuses and the height is one of the legs. This means the height of the triangular section is \dfrac4{3(\sqrt2)^2}\sqrt{9-{x_0}^2}=\dfrac23\sqrt{9-{x_0}^2}.

Finally, x_0 can be chosen from any value in -3\le x_0\le3. We're now ready to set up the integral to find the volume of the solid. The volume is the sum of the infinitely many triangular sections' areas, which are

\dfrac12\left(\dfrac43\sqrt{9-{x_0}^2}\right)\left(\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac49(9-{x_0}^2)

and so the volume would be

\displaystyle\int_{x=-3}^{x=3}\frac49(9-x^2)\,\mathrm dx
=\left(4x-\dfrac4{27}x^3\right)\bigg|_{x=-3}^{x=3}
=16

6 0
3 years ago
Use the integer tiles to find the quotient: 36 ÷ 6 = 6
Sonja [21]

Answer:

x=6

Step-by-step explanation:

Suppose x is 36÷6

x=36÷6

x=6

6 0
3 years ago
Read 2 more answers
Given: Line JK is congruent to Line NK A is the midpoint of Line JN Prove: Triangle JAK is congruent to Triangle NAK
andrew11 [14]
Can u take a Picture of the triangle
7 0
4 years ago
Read 2 more answers
Please help I don't know how to do this​
OverLord2011 [107]
You literally just need to click yes then call it a day it’s simple don’t worry too much :D
6 0
3 years ago
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