Please help I don't know how to do this

Geraldo recently saw a newspaper ad for a new version of his laptop. the projected price is $400.00, and the laptop will be out

Tanya [424]

The amount he had to pay if he have to purchase a laptop today that is the same value as the one he saw in the ad is $ 390.24.

Given that:-

Price of the laptop after 1 year = $ 400.

Inflation rate = 2.5 %

We have to find the amount he had to pay if he have to purchase a laptop today that is the same value as the one he saw in the ad.

Let the price he had to pay be x.

Hence, we can write,

x + (x*(2.5)*1)/100 = 400

x(1 + 1/40) = 400

x(41/40) = 400

x = 400*40/41 = $ 16000/41 = $ 390.24.

To learn more about amount, here:-

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5 0

1 year ago

The equations x minus 2 y = 1, 3 x minus y = negative 1, x + 2 y = negative 1, and 3 x + y = 1 are shown on the graph below. On

Basile [38]

Answer: (a) x + 2y = -1 and 3x + y = 1

Step-by-step explanation:

I am not sure what the purpose was for the colored lines but I included them on the graph (below).

6 0

3 years ago

Read 2 more answers

Math please help !!!!!

bixtya [17]

Answer:

hope it helped

Step-by-step explanation:

2nd one is the answer

7 0

2 years ago

Time spent using e-mail per session is normally distributed, with mu equals 11 minutes and sigma equals 3 minutes. Assume that

liq [111]

Answer:

a) 0.259

b) 0.297

c) 0.497

Step-by-step explanation:

To solve this problem, it is important to know the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 11, \sigma = 3$

a. If you select a random sample of 25 sessions, what is the probability that the sample mean is between 10.8 and 11.2 minutes?

Here we have that $n = 25, s = \frac{3}{\sqrt{25}} = 0.6$

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{11.2 - 11}{0.6}$

$Z = 0.33$

$Z = 0.33$ has a pvalue of 0.6293.

X = 10.8

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.8 - 11}{0.6}$

$Z = -0.33$

$Z = -0.33$ has a pvalue of 0.3707.

0.6293 - 0.3707 = 0.2586

0.259 probability, rounded to three decimal places.

b. If you select a random sample of 25 sessions, what is the probability that the sample mean is between 10.5 and 11 minutes?

Subtraction of the pvalue of Z when X = 11 subtracted by the pvalue of Z when X = 10.5. So

X = 11

$Z = \frac{X - \mu}{s}$

$Z = \frac{11 - 11}{0.6}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

X = 10.5

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.5 - 11}{0.6}$

$Z = -0.83$

$Z = -0.83$ has a pvalue of 0.2033.

0.5 - 0.2033 = 0.2967

0.297, rounded to three decimal places.

c. If you select a random sample of 100 sessions, what is the probability that the sample mean is between 10.8 and 11.2 minutes?

Here we have that $n = 100, s = \frac{3}{\sqrt{100}} = 0.3$

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{11.2 - 11}{0.3}$

$Z = 0.67$

$Z = 0.67$ has a pvalue of 0.7486.

X = 10.8

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.8 - 11}{0.3}$

$Z = -0.67$

$Z = -0.67$ has a pvalue of 0.2514.

0.7486 - 0.2514 = 0.4972

0.497, rounded to three decimal places.

5 0

3 years ago

Please answer the question below | | | v

miskamm [114]

Answer:

The last/bottom graph

Step-by-step explanation:

I would assume it the bottom on because when you reflect off the y-axis, you don't reflect of the y-axis line. You reflect of the x-axis, it is weird.

3 0

3 years ago

Please help I don't know how to do this​

Please help I don't know how to do this