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Mathematics

1 answer:

loris [4]3 years ago

7 0

Remember that both the denominator and the square root function cannot have values less than 0. So to figure what values can go into each we need to do a little math. Set both the denominator and the under the radical equal to 0
x + 2 = 0 x - 3 = 0
x = -2 x = 3

Since they must be those numbers or bigger 3 is the larger of the 2 the final answer is
x >= 3 Type in greater than into the box

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Using the standard 28/36 guidelines, what is the maximum mortgage payment allowed for someone with an annual salary of $73,025?

nekit [7.7K]

The maximum mortgage payment allowed for someone with an annual salary of $73.025 would be $2,190.75 per month, so the correct option is A.

<h2><u>How to determine the amount using the standard 28/36 guides?</u></h2>

To determine, using the standard 28/36 guidelines, what is the maximum mortgage payment allowed for someone with an annual salary of $73,025, the following calculation must be made:

((73025 x 36) / 100) / 12 = X
(2,628,900 / 100) / 12 = X
26,289 / 12 = X
2,190.75 = X

Therefore, the maximum mortgage payment allowed for someone with an annual salary of $73.025 would be $2,190.75 per month.

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4 0

2 years ago

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$