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Roman55 [17]
3 years ago
13

Write an equation of the line passing through point p that is perpendicular to the given line. p(3,1), y=13x−5

Mathematics
1 answer:
Anarel [89]3 years ago
7 0
You know two lines y=ax+b and y=mx+n that are perpendicular, so we have the product a*m=-1

+ This line is perpendicular to y=13x-5, so it has equation: y=-1/13x+b
+ And it passes through the point (3;1), so we have x=3, y=1. So 1=-1/13 *3+b
and b= 1+3/13= 16/13
And we have y=-1/13x+16/13
Have fun
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If f (x)=3x, g(x)=x-3, and h(x)= square root of x, find (fogoh)(25)
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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
sashaice [31]

Answer:

k = –10

Step-by-step explanation:

From the question given above, the following data were obtained:

f(x) = x³ – 6x² – 11x + k

Factor => x + 2

Value of K =?

Next, we shall obtained the value of x from x + 2. This is illustrated below:

x + 2 = 0

Collect like terms

x = 0 – 2

x = –2

Finally, we shall determine the value of k as illustrated below:

f(x) = x³ – 6x² – 11x + k

x = –2

Thus,

f(–2) = 0

x³ – 6x² – 11x + k = 0

(–2)³ – (–2)² – 11(–2) + k = 0

–8 – (4) + 22 + K = 0

–8 – 4 + 22 + K = 0

10 + k = 0

Collect like terms

k = 0 – 10

k = –10

Thus, the value of k is –10

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Answer:

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