3 years ago

Write an equation of the line passing through point p that is perpendicular to the given line. p(3,1), y=13x−5

1 answer:

7 0

You know two lines y=ax+b and y=mx+n that are perpendicular, so we have the product a*m=-1

+ This line is perpendicular to y=13x-5, so it has equation: y=-1/13x+b
+ And it passes through the point (3;1), so we have x=3, y=1. So 1=-1/13 *3+b
and b= 1+3/13= 16/13
And we have y=-1/13x+16/13
Have fun

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A newsboy notices he has four times as many dimes as quarters. if his dimes and quarters total$1.95, how many of each has he?

MrRissso [65]

D=4q
25q+10d=195
5q+2d=39

sub 4q foro d
5q+2(4q)=39
5q+8q=39
13q=39
divide 13
q=3

d=4q
d=4(3)
d=12

12 dimes
3 quarters

4 0

3 years ago

The coordinates of trapezoid ABCD are A(−4, 3), B(2, 3), C(4, −1) and D(−4, −1). A line segment runs through the trapezoid with

madam [21]

The distance from point Y to the y-axis is 4 units and the distance from point Z to the y-axis is 3 units, then the lelgth of the segment YZ is 4+3=7 units.
If <span>a scale factor is 3, then the length of Y'Z' will be 7·3=21 units.
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P.S. In the added picture you can see trapezoid ABCD that was dilated by a scale factor 3 about the origin. This may help to understand that all linear values after dilation become multiplied by scale factor.
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