true or false: for most queries, the user location changes our understanding of the query and user intent.

Gps has fostered many benefits in our society, but have also added some risks. What is a risk of gps?

kozerog [31]

GPS is a global positioning system that tells direction and routes. Some risks that come along with GPS are inaccuracy, distraction, and lack of knowledge.

GPS is a radio navigation system based on the satellite and is used to navigate the directions with the help of the signals. Though it has many benefits also has disadvantages. It sometimes does not show accurate routes and direction that is too long.

The navigation system causes distraction during driving and may cause an accident. Too much reliance on GPS causes a lack of knowledge in remembering the directions and places. It may sometimes lead to crime as the saved information and be leaked.

Therefore, GPS has advantages and disadvantages too.

Learn more about GPS here:

brainly.com/question/6905079

#SPJ4

5 0

2 years ago

Concentric circles on a disk platter where data is stored;________

bagirrra123 [75]

Answer:

Tracks

Resilient File System (ReFS)

Explanation:

Concentric circles on a disk platter where data is stored is called Tracks
The new file system developed for Windows Server 2012 is called Resilient File System (ReFS). It allows increased stability for disk storage and improved features for data recovery and error checking

4 0

3 years ago

Write a program that (a) generates a vector with 20 random integer elements with integers between -29 and 30, (b) replaces all t

Ghella [55]

Answer:

import random

randomlist = []

for i in range(0,20):

n = random.randint(-29,30)

if n < 0 :

n = 100

randomlist.append(n)

print(randomlist)

Explanation:

The random module is first imported as it takes care of random. Number generation.

An empty list called randomliay is created to hold the generated random integers.

Using a for loop, we specify the range of random numbers we want.

Inside the for loop ; we attach our generated random integer which will be in the range (-29 to 30) in a variable n

For each n value generated, if the value is less than 0( it is negative, since all the values are integers), replace the value with 100.

5 0

2 years ago

Your co-worker is at a conference in another state. She requests that you

aniked [119]

Answer:

C

Explanation:

This is the easiest, quickest, and least destructive method.

3 0

3 years ago

2. Consider a 2 GHz processor where two important programs, A and B, take one second each to execute. Each program has a CPI of

allsm [11]

Answer:

program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

Explanation:

Finding number of instructions in A and B using time taken by the original processor :

The clock speed of the original processor is 2 GHz.

which means each clock takes, 1/clockspeed

= 1 / 2GH = 0.5ns

Now, the CPI for this processor is 1.5 for both programs A and B. therefore each instruction takes 1.5 clock cycles.

Let's say there are n instructions in each program.

therefore time taken to execute n instructions

= n * CPI * cycletime = n * 1.5 * 0.5ns

from the question, each program takes 1 sec to execute in the original processor.

therefore

n * 1.5 * 0.5ns = 1sec

n = 1.3333 * 10^9

So, number of instructions in each program is 1.3333 * 10^9

the new processor :

The cycle time for the new processor is 0.6 ns.

Time taken by program A = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.1 * 0.6ns

= 0.88 sec

Time taken by program B = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.4 * 0.6

= 1.12 sec

Now, program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

5 0

2 years ago