You have to use implicit derivative
dy / dx = y'
xy^3+y=3x
y^3 + 3xy^2 y' + y' = 3
[3xy^2 + 1) y'= 3 - y^3
3 - y^3
y' = ----------------- <-----------answer
3xy^2 + 1
Answer:
Multiply each side by 6
Step-by-step explanation:
27 = m/6 - 3
Add 3 to each side
27+3 = m/6 - 3+3
30 = m/6
Multiply each side by 6
30*6 = m/6*6
180 = m
Answer:
Angle 1 is 57 degrees
Angle 3 is 57 degrees
Angle 4 is 123 degrees
Step-by-step explanation:
Cause a straight line is 180 degrees and if angle 2 is 123 degress then angle 3 is 57 degrees and i got that by Subtracting 180-123 =57
Then for angles one you do the same maththat you do for finding angle 3
Then for angles 4 subtract 180-57=123
Answers:
a = -6/37
b = -1/37
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Explanation:
Let's start things off by computing the derivatives we'll need

Apply substitution to get

I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.
The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero
a-6b = 0
a = 6b
At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)
-6a -b = 1
-6(6b) - b = 1 .... plug in a = 6b
-36b - b = 1
-37b = 1
b = -1/37
Use this to find 'a'
a = 6b
a = 6(-1/37)
a = -6/37
Answer:
16
Step-by-step explanation:
16 divided by 4=4
16+4=20
20 divided by 5=4