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jonny [76]
3 years ago
5

Wilma works at a bird sanctuary and stores birdseed in plastic containers. She has 2 small containers that hold 8 pounds of bird

seed each and 9 large containers that hold 12 pounds of birdseed each. Each container was full until she used 4 pounds of bird seed. She wants to put some of the remaining birdseed into 30 bird feeders that can hold 2 pounds each.
Mathematics
1 answer:
Amanda [17]3 years ago
3 0

Answer:

 60 lbs left over

Step-by-step explanation:  Since the small containers hold 8 lbs each you multiply 8 by 2 since there are 2 containers. Same for the large, multiply 9 by 12 because each container holds 12 lbs and there is 9 containers. Then, you subtract 4 from that total because she already used 4 lbs.

x=(2*8)+(9*12)-4 Multiply

x=16+108-4 Simplify

x=120

So, before she fills the bird feeders she has 120 lbs of bird seed. There are 30 bird feeders and since they hold 2 lbs each you multiply 30 and 2. Then you subtract that from the 120 lbs because she is filling the bird feeders with that seed.

120- (30*2)

120-60= 60 lbs left over

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Solve each equation.<br> 1/3a = -5 a = ?<br> 12 - b = 12.5 b = ? <br> -0.1 = -10c c = ?
Rina8888 [55]

Answer:

a = -15, b = -.5, c = -1

Step-by-step explanation:

1/3a = -5 --> multiply each side with 3 --> a = -15

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Car A, traveling at a constant 10 m/s, crosses the start line 3 seconds before Car B, who is traveling at a constant 15 m/s. At
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The distance between Car A and car B,When Car A crosses the start line is:
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time of car A=t

x=10 m/st  ⇒    x=10t    (1)

Distance traveled by car B=x
time of car B=t-3

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With the equations (1) and (2) we make a system of equations:

x=10t
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We solve this system of equations:

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