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jonny [76]
3 years ago
5

Wilma works at a bird sanctuary and stores birdseed in plastic containers. She has 2 small containers that hold 8 pounds of bird

seed each and 9 large containers that hold 12 pounds of birdseed each. Each container was full until she used 4 pounds of bird seed. She wants to put some of the remaining birdseed into 30 bird feeders that can hold 2 pounds each.
Mathematics
1 answer:
Amanda [17]3 years ago
3 0

Answer:

 60 lbs left over

Step-by-step explanation:  Since the small containers hold 8 lbs each you multiply 8 by 2 since there are 2 containers. Same for the large, multiply 9 by 12 because each container holds 12 lbs and there is 9 containers. Then, you subtract 4 from that total because she already used 4 lbs.

x=(2*8)+(9*12)-4 Multiply

x=16+108-4 Simplify

x=120

So, before she fills the bird feeders she has 120 lbs of bird seed. There are 30 bird feeders and since they hold 2 lbs each you multiply 30 and 2. Then you subtract that from the 120 lbs because she is filling the bird feeders with that seed.

120- (30*2)

120-60= 60 lbs left over

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You have to use implicit derivative

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xy^3+y=3x

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[3xy^2 + 1) y'= 3 - y^3

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y' = -----------------   <-----------answer
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6 0
3 years ago
NO LINKS NO FILES. After you add 3 to both sides of the equation 27 = m/6 - 3, what should you do next?
a_sh-v [17]

Answer:

Multiply each side by 6

Step-by-step explanation:

27 = m/6 - 3

Add 3 to each side

27+3 = m/6 - 3+3

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3 years ago
Find the missing angle measure. PLEASE HELP ASAP
kobusy [5.1K]

Answer:

Angle 1 is 57 degrees

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Step-by-step explanation:

Cause a straight line is 180 degrees and if angle 2 is 123 degress then angle 3 is 57 degrees and i got that by Subtracting 180-123 =57

Then for angles one you do the same maththat you do for finding angle 3

Then for angles 4 subtract 180-57=123

6 0
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Find constants a and b such that the function y = a sin(x) + b cos(x) satisfies the differential equation y'' + y' − 5y = sin(x)
vichka [17]

Answers:

a = -6/37

b = -1/37

============================================================

Explanation:

Let's start things off by computing the derivatives we'll need

y = a\sin(x) + b\cos(x)\\\\y' = a\cos(x) - b\sin(x)\\\\y'' = -a\sin(x) - b\cos(x)\\\\

Apply substitution to get

y'' + y' - 5y = \sin(x)\\\\\left(-a\sin(x) - b\cos(x)\right) + \left(a\cos(x) - b\sin(x)\right) - 5\left(a\sin(x) + b\cos(x)\right) = \sin(x)\\\\-a\sin(x) - b\cos(x) + a\cos(x) - b\sin(x) - 5a\sin(x) - 5b\cos(x) = \sin(x)\\\\\left(-a\sin(x) - b\sin(x) - 5a\sin(x)\right)  + \left(- b\cos(x) + a\cos(x) - 5b\cos(x)\right) = \sin(x)\\\\\left(-a - b - 5a\right)\sin(x)  + \left(- b + a - 5b\right)\cos(x) = \sin(x)\\\\\left(-6a - b\right)\sin(x)  + \left(a - 6b\right)\cos(x) = \sin(x)\\\\

I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.

The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero

a-6b = 0

a = 6b

At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)

-6a  -b = 1

-6(6b) - b = 1 .... plug in a = 6b

-36b - b = 1

-37b = 1

b = -1/37

Use this to find 'a'

a = 6b

a = 6(-1/37)

a = -6/37

8 0
3 years ago
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densk [106]

Answer:

16

Step-by-step explanation:

16 divided by 4=4

16+4=20

20 divided by 5=4

8 0
3 years ago
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