Calculate dy/dx when xy^3 + y =3x

1 answer:

6 0

You have to use implicit derivative

dy / dx = y'

xy^3+y=3x

y^3 + 3xy^2 y' + y' = 3

[3xy^2 + 1) y'= 3 - y^3

          3 - y^3
y' = -----------------   <-----------answer
         3xy^2 + 1

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