The probability that the sample proportion is within ± 0.02 of the population proportion is 0.3328
<h3>How to determine the probability?</h3>
The given parameters are:
- Sample size, n = 100
- Population proportion, p = 82%
Start by calculating the mean:
Calculate the standard deviation:
Within ± 0.02 of the population proportion are:
Calculate the z-scores at these points using:
So, we have:
The probability is then represented as:
P(x ± 0.02) = P(-0.43 < z < 0.43)
Using the z table of probabilities, we have:
P(x ± 0.02) = 0.3328
Hence, the probability that the sample proportion is within ± 0.02 of the population proportion is 0.3328
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Answer:
2. 135
3. 8
4. 9/49 or 0.18367346…
5. b2/125
Step-by-step explanation:
( I couldn't see what b was equal to if you showed it. And the b2 is b squared)
2.085 x 10^6 =
move the decimal 6 places to the right: 2,085,000
Answer:
5x +6y -90 = 0
Step-by-step explanation:
The perpendicular line will have the x- and y-coefficients swapped, and one of them negated. The constant will be chosen so the equation is satisfied at the given point.
5x +6y = 5(6) +6(10) = 90
The equation of the perpendicular line in general form is ...
5x +6y -90 = 0
Answer:
Well Bree if Camille had 30 dollars to spend on 3 gifts you will have to figure out how much each gift was and then you will subtract the rest off that.
