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denis-greek [22]
3 years ago
12

How would I graph this inequality?

a1" title="7x+3y\ \textless \ 6-5x" alt="7x+3y\ \textless \ 6-5x" align="absmiddle" class="latex-formula">

Mathematics
1 answer:
Anon25 [30]3 years ago
3 0

Answer:

the graph in the attached figure

Step-by-step explanation:

we have

7x+3y

isolate the variable y

Subtract 7x both sides

3y

3y

Divide by 3 both sides

y

The solution of the inequality is the shaded area below the dashed line

The equation of the shaded line is y=-4x+2

The slope of the dashed line is negative m=-4

The y-intercept of the dashed line is the point (0,2)

The x-intercept of the dashed line is the point (0.5,0)

To graph the inequality plot the intercepts and shade the area below the dashed line

using a graphing tool

the graph in the attached figure

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3(x - 5) = 6 solve the equation
pshichka [43]

____________________________________________________

Solve for x:

3(x - 5) = 6

Distribute the 3 to the variables inside the parenthesis

3x - 15 = 6

Add 15 to both sides to cancel out the "-15"

3x = 21

Divide both sides by 3

x = 7

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8 0
2 years ago
Read 2 more answers
Explain the meaning of zero in each situation.<br> What is the opposite of the opposite of -12?
oee [108]
The opposite of -12 is 12
5 0
2 years ago
Write the set of real numbers x less than 6 in set builder notation
maksim [4K]

Answer:

{x ∈ R: x<6}

Step-by-step explanation:

Given

  • x is a real number
  • x is less than 6

Required

Write the set using set builder notation

The very first thing to do is to list out the range of x, using inequalities;

x is less than 6 implies that -infiniti < x < 6

The next step is to translate this to set builder. This is done as follows

x ∈ R - > This means that x is a real number

x < 6 -> where x is less than 6.

Bringing these two together, it gives:

{x ∈ R: x<6}

Hence, the set of real numbers x less than 6 is equivalent to {x ∈ R: x<6} using set builder notation

6 0
2 years ago
One end of a ramp is raised to the back of a truck 1 meter
Bogdan [553]

Answer:

26.6°

Step-by-step explanation:

8 0
3 years ago
Find the Maclaurin polynomials of orders n = 0, 1, 2, 3, and 4, and then find the nth Maclaurin polynomials for the function in
Zielflug [23.3K]

Answer:

Σ(-1)^kx^k for k = 0 to n

Step-by-step explanation:

The nth Maclaurin polynomials for f to be

Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......

The given function is.

f(x) = 1/(1+x)

Differentiate four times with respect to x

f(x) = 1/(1+x)

f'(x) = -1/(1+x)²

f''(x) = 2/(1+x)³

f'''(x) = -6/(1+x)⁴

f''''(x) = 24/(1+x)^5

To calculate with a coefficient of 1

f(0) = 1

f'(0) = -1

f''(0) = 2

f'''(0) = -6

f''''(0) = 24

Findinf Pn(x) for n = 0 to 4.

Po(x) = 1

P1(x) = 1 - x

P2(x) = 1 - x + x²

P3(x) = 1 - x+ x² - x³

P4(x) = 1 - x+ x² - x³+ x⁴

Hence, the nth Maclaurin polynomials is

1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n

= Σ(-1)^kx^k for k = 0 to n

6 0
3 years ago
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