The answer is 87. it was quite simple
Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
Learn more about trigonometry here : brainly.com/question/7331447
#SPJ9
Answer:
0.54
Step-by-step explanation:
You take 54 and divide it by 100
54/100 =0.54
Hope this helps!!
Answer:
m = 10/3
<em>(as a decimal: m = 3.333...)</em>
<em />
Step-by-step explanation:
5m - 8 = 2m + 2
5m - 8 = 2m + 2
- 2m - 2m <em>(make all "m" on one side to isolate variable)</em>
3m - 8 = 2
+ 8 + 8 <em>(get m entirely on 1 side)</em>
3m = 10
÷3 ÷3 <em>(divide by 3 to get 1m)</em>
m = 10/3
<em>(as a decimal: m = 3.333...)</em>
<em />
<em />
hope this helps!! have a lovely day :)
