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Marysya12 [62]
3 years ago
6

How is 0.808 minus 1?

Mathematics
2 answers:
AleksandrR [38]3 years ago
6 0

Answer:

Not sure what you are talking about, but i think the answer is -0.192

Step-by-step explanation:

Vedmedyk [2.9K]3 years ago
6 0

Answer:

-0.192

Step-by-step explanation:

0.808-1=-0.192

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Find the sum of the first 9 terms in the following geometric series. 64+32+16+
Dafna11 [192]

Answer:

The sum of the first 9 terms in the geometric series is 127.75

Step-by-step explanation:

In the geometric series, there is a constant ratio between each two consecutive numbers

<u>Examples:</u>

5,  10,  20,  40,  80,  ………………………. (×2)

5000,  1000,  200,  40,  …………………………(÷5)

General term (nth term) of a Geometric series is

<em>a1</em> = <em>a</em>, <em>a2</em> = <em>ar</em>, <em>a3</em> = <em>ar</em>²,  <em>a4</em> = <em>ar</em>³, ..........

an=ar^{n-1}, where

<em>a </em>is the first term

r is the constant ratio between each two consecutive terms

The sum of the first <em>n</em> terms of a Geometric series is calculated by this rule

Sn=\frac{a(1-r^{n})}{1-r}

Let us solve the question

∵ The geometric series is 64, 32, 16, .......................

∴ <em>a </em>= 64

∴ <em>r </em>= 32 ÷ 64 = 0.5

→ We need to find the sum of the first 9 terms

∴ <em>n</em> = 9

→ Substitute these values on the formula of the sum above

∴ S9=\frac{64(1-0.5^{9})}{1-0.5}

→ use the calculator to find the answer

∴ <em>S</em>9 = 127.75

 ∴ The sum of the first 9 terms in the geometric series is 127.75

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How can turn a percentage to a fraction
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Rationalise:<br>(1)              4/(2+root3+root7)<br>(2)              4/(2root3+root5)
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=\frac{6\sqrt3-6\sqrt7+6\sqrt7-14\sqrt3-12+4\sqrt{21}}{-12}=\frac{-8\sqrt3+4\sqrt{21}-12}{-12}=\frac{-4(2\sqrt3-\sqrt{21}+3)}{-12}\\\\=\frac{2\sqrt3-\sqrt{21}+3}{3}

==============================================================

\frac{4}{2\sqrt3+\sqrt5}\cdot\frac{2\sqrt3-\sqrt5}{2\sqrt3-\sqrt5}=\frac{8\sqrt3-4\sqrt5}{(2\sqrt3)^2-(\sqrt5)^2}=\frac{8\sqrt3-4\sqrt5}{4\cdot3-5}=\frac{8\sqrt3-4\sqrt5}{12-5}\\\\=\frac{8\sqrt3-4\sqrt5}{7}
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