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padilas [110]
3 years ago
7

The half-life of krypton-91 (91Kr) is 10 s. At time t = 0 a heavy canister contains 3 g of this radioactive gas. Find a function

m(t) = m02−t/h that models the amount of 91Kr remaining in the canister after t seconds.
Mathematics
1 answer:
Amanda [17]3 years ago
3 0
The answer is m(t) = 3.2 -t/10
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4 years ago
Simplify (3 + 2i)(7 − 5i).
erma4kov [3.2K]
Rule needed: i^2 = -1
Standard form a + bi

(3 + 2i)(7 - 5i) FOIL
3 * 7 = 21
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Putting it all back together.
31 - i
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3 years ago
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ivann1987 [24]

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Step-by-step explanation:

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