Is x3 an exponent ? i answered one of ur earlier questions and i assumed x3 was multiplication
9 + (7 - 1)^3
= 9 + (6)^3
= 9 + (216)
= 225
or if it is multiplication...
then the answer is 27
F(x) = 2(x + 6) Plug in 22 for x
F(22) = 2(22 + 6) Use the Distributive Property
F(22) = 44 + 12 Add
F(22) = 56
Answer:42
Step-by-step explanation:
V= 18 + 6(4)
V= 18 + 24
V= 42
-2,3 is (x1,y1) and (4,-5) is (x2,y2) so you do y2-y1/x2-x1
y2-y1 is -5-3 which is -8 and x2-x1 is 4-(-2) which is 6 so you get
-8/6= -4/3