3 years ago

The image from reflecting a figure in the third quadrant over the x-axis

1 answer:

4 0

When an object that is in the third quadrant is refrected over the x-axis, the image is in the 2nd quadrant.

Therefore, the image from refrecting a figure in the third quadrant over the x-axis is in the second quadrant.

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What is the surface area of the given figure?

denis23 [38]

Answer:

Step-by-step explanation:

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6 0

3 years ago

InWrite the equation of the line that passes through (7, - 4) and (- 1, 2) slope- intercept form.

blondinia [14]

Answer:

General Equation of a Line

$General Equation \\(y - y_{1} )= m (x-x_{1}) \\Slope=m= \frac{x_{2}-x_{1} }{y_{2}-y_{1} } \\\\Given:\\p_{1}=(7,-4)\\p_{2}=(-1,2)\\Solution:\\m=(\frac{-1-7}{2-(-4)}) =\frac{-8}{6}\\y-(-4) = (\frac{-8}{6} )(x-7)\\y+4=\frac{-8x}{6} + 56\\y=\frac{-8x}{6} + 52 \\\\The\\ equation \\ is \\ y=\frac{-8x}{6} + 52$