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MAXImum [283]
3 years ago
8

Find the angle 0 between the vectors. u=(1, 1, 1, 0), v = (4, 4, 4, 4).

Mathematics
1 answer:
Naya [18.7K]3 years ago
6 0

Answer:

30 degrees

Step-by-step explanation:

u dot v=1*4+1*4+1*4+0*4=4+4+4+0=12

|u|=sqrt(1^2+1^2+1^2+0^2)=sqrt(3)

|v|=sqrt(4^2+4^2+4^2+4^2)=sqrt(4*4^2)=2*4=8

cos(theta)=u dot v/(|u||v|)

cos(theta)=12/(sqrt(3)*8)

cos(theta)=3/(sqrt(3)*2)

cos(theta)=sqrt(3)/2

theta=30 degrees

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In triangle abc, the angle c is six times as large as angle
mote1985 [20]
The interior angles of a triangle add up to 180 degrees

a = 1st angle, b = 2nd angle, c = 3rd angle

c = 6a
b = a + 60
a + b + c = 180

a + (a + 60) + (6a) = 180
8a + 60 = 180
8a = 180 - 60
8a = 120
a = 120/8
a = 15 <=== here is one angle

b = a + 60
b = 15 + 60
b = 75 <=== and another one

c = 6a
c = 6(15)
c = 90 <=== and the last angle

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2 years ago
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Answer:

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Step-by-step explanation:

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\huge \bf༆ Answer ༄

Let's simply ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: - 5 {x}^{2} (4x - 6 {x}^{2}  - 3)

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{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: - 20 {x}^{3}  + 30 {x}^{4}  + 15 {x}^{2}

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:30 {x}^{4}  - 20 {x}^{3}  + 15 {x}^{2}

5 0
2 years ago
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NeTakaya

Answer:

Step-by-step explanation:

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6 ·2 + 1

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answer is 13

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Answer:

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Step-by-step explanation:

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