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3 years ago

Lowest positive integer greater than 1 when divided by 5 or 8 leaves 1 remainder

Mathematics

1 answer:

alex41 [277]3 years ago

8 0

40
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Exercise 18.14. Toy defects. Workers at a factory produce a toy with a defect about once every 4 hours on average. Each toy cost

ohaa [14]

Answer: $70

Step-by-step explanation:

Given that:

Toy with defect is produced once every 4 hours

Cost of labor and supplies incurred for producing a defective toy = $7

Number of defective toys that is expected to be produced in a 40 hour work week :

Number of hours / average hour for producing 1 defective toy

= 40/ 4

= 10 defective toys

Cost incurred for producing 10 defective toys :

($7 * 10) = $70

6 0

3 years ago

Find the volume of a right circular cone that has a height of 9.6m and a base with a diameter of 2.9m. Round your answer to the

Vlad [161]

Answer:

$r = \frac{D}{2}= \frac{2.9m}{2}= 1.45 m$

If we convert the height to meters like this:

$h = 9.6 cm *\frac{1m}{100 cm}= 0.096m$

And we want to find the volume of the cone and is given by:

$V = \pi r^2 h$

And replacing we got:

$V = \pi (1.45m)^2 (0.096m) =0.634 m^3 \approx 0.6 m^3$

Step-by-step explanation:

For this case we have a right circular cone with a height of 9.6cm and a base with a diameter of 2.9m. We can find the radius like this:

$r = \frac{D}{2}= \frac{2.9m}{2}= 1.45 m$

If we convert the height to meters like this:

$h = 9.6 cm *\frac{1m}{100 cm}= 0.096m$

And we want to find the volume of the cone and is given by:

$V = \pi r^2 h$

And replacing we got:

$V = \pi (1.45m)^2 (0.096m) =0.634 m^3 \approx 0.6 m^3$

4 0

3 years ago

What shape is the base? What is the area of the<br> base (B)?

VladimirAG [237]

Answer:

rectangular; 32 in²

Step-by-step explanation:

The base is rectangular, because 1 set of sides is longer than the other.

To find the area of the base, multiply 4 by 8 to get 32 in².

6 0

3 years ago

Which of the following is(are) the solution(s) to | 3x + 10 | = 10

aleksandr82 [10.1K]

$|3x+10|=10\iff3x+10=10\ \vee\ 3x+10=-10\qquad|-10\\\\3x=0\ \vee\ 3x=-20\qquad|:3\\\\\boxed{x=0\ \vee\ x=-\dfrac{20}{3}}$

8 0

3 years ago

Read 2 more answers

Malik's solution to the equation 2/5x-4y=10 when x=60 is shown below

Hatshy [7]

Answer:

D. Malik substituted 60 for y instead of x.

Step-by-step explanation:

3 0

3 years ago