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zepelin [54]
4 years ago
10

Is there a way i can add graphs on here ?

Mathematics
1 answer:
lisov135 [29]4 years ago
7 0
Yes when u post it there would be a paperclip and click it and you schould be able to put a photo up
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Raphael graphed the system of equations shown.
Vanyuwa [196]

Answer:

(–2.2, –3)

Step-by-step explanation:

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3 years ago
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Find the distance between each pair of points. Round to the nearest hundredth (-8,-2) and (6,-1)
elena-s [515]

Answer:

Use the distance formula to determine the distance between two points.

Exact Form:

√

197

Decimal Form:

14.03566884

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Step-by-step explanation:

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3 years ago
Find the unknown size <br>please I really need answers ​
katen-ka-za [31]

Answer:

z=80°<em><u>(</u></em><em><u>corresponding</u></em><em><u> </u></em><em><u>angles)</u></em>

<em><u>x+z=180°(linear \: pair \: ) \\ 80°  + x = 180°  \\ x= 100°</u></em>

<em><u>y=</u></em><em><u>100 </u></em><em><u>° </u></em><em><u>(</u></em><em><u>alternate</u></em><em><u> </u></em><em><u>angles</u></em><em><u>)</u></em>

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8 0
2 years ago
Not sure which one is it<br><br>plz help
viva [34]
The last one is correct answer
7 0
3 years ago
“write an inequality to represent the graph.”
zhuklara [117]

Answer:

The inequality for the given graph is y>\frac{2}{3}x-1.

Step-by-step explanation:

From the given graph it noticed that the line passing through (0,-1) and (3,1).

The equation of line passing through two points is defined as

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The equation of line is

y+1=\frac{1+1}{3-0}(x-0)

y+1=\frac{2}{3}x

y=\frac{2}{3}x-1

Therefore the related equation is y=\frac{2}{3}x-1.

The point (0,0) lies in the shaded region, therefore the point (0,0) is the solution of required inequality.

Put (0,0) in the related equation.

0=\frac{2}{3}(0)-1

0=-1

Since 0 is greater than -1, therefore the sign of inequality must be >. The related line is a dotted line, therefore we cannot use \geq.

Therefore the required inequality is

y>\frac{2}{3}x-1

8 0
3 years ago
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