Amount owed at the end of 1 year is 3640
<h3><u>Solution:</u></h3>
Given that yoko borrows $3500.
Rate of interest charged is 4% compounded each year
Need to determine amount owed at the end of 1 year.
In our case
:
Borrowed Amount that is principal P = $3500
Rate of interest r = 4%
Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1
<em><u>Formula for Amount of compounded yearly is as follows:</u></em>
Where "p" is the principal
"r" is the rate of interest
"n" is the number of years
Substituting the values in above formula we get
Hence amount owed at the end of 1 year is 3640
Hello!
Answer:
1) 7k+35
2) 9n−36
3) 4x+22
Step-by-step explanation:
1) 7(k+5)
1) 7k+7×5
1) 7k+35
2) 9(n-4)
2) 9n+9×−4
2) 9n−36
3) 4(x+5)+2
3) 4x+20+2
3) 4x+(20+2)
3) 4x+22
Hope this helps!
Answer:
B. 30x
D. x(45-15)
Step-by-step explanation:
The distributive property lets you factor out the common factor of x. The sum of coefficients can be simplified to a single coefficient.
45x -15x = x(45 -15) = 30x
Answer: a) about 450
Step-by-step explanation:
50 multiplied by 9 is 450 and its asking for an approximate so it would be anything near 450
<span>A container holds 15 pennies, 8 nickels, and 10 dimes.
You will randomly select two coins without replacement.
-->Fill in the probabilities on a tree diagram.</span>
