Given:
A point divides a directed line segment from (-6, -3) to (5,8) into a ratio of 6 to 5.
To find:
The coordinates of that point.
Solution:
Section formula: If point divides a line segment in m:n, then the coordinates of that point are
A point divides a directed line segment from (-6, -3) to (5,8) into a ratio of 6 to 5. Using section formula, we get
Therefore, the coordinates of the required point are (0,3).
Step-by-step explanation:
this is only what i got from this question. it may be the only thing we need to do.. or not. but this step is correct for sure
The range of the quadratic function is [-1, ∞) after plotting the function on the coordinate plane.
<h3>What is a function?</h3>It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
It is given that:
The function is:
f(x) = (x - 4)(x - 2)
The above function is a quadratic function.
The above function can be written as:
f(x) = x² - 6x + 8
From the graph,
The minimum value of graph at x = 3 is y = -1
The range of the function is [-1, ∞)
Thus, the range of the quadratic function is [-1, ∞) after plotting the function on the coordinate plane.
Learn more about the function here:
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