Answer:
(a) 12 hours
(b) $220
Step-by-step explanation:
(a) First we plug in $364 for C
C=76+24h
364=76+24h
Subtract 76 from both sides
24h=288
Divide both sides by 24
h=12
She spent 12 hours fixing the drain
(b) First we plug 6 hours in for h
C=76+24(6)
Multiply it out
C=76+144
Add
C=220
It costs $220 for fixing a drain that takes 6 hours
I’m pretty sure it would be a and b
Answer:
For this case, the first thing we must do is define variables:
x: number of hammers
y: number of wrenches
We write the system of inequations:
10x + 6y <= 120
x + y> = 14
Step-by-step explanation:
You did not include the choices. However, I answered one that just included them. I've included the possible answers below and then the correct answers.
<span>A multiple of Equation 1.
B. The sum of Equation 1 and Equation 2
C. An equation that replaces only the coefficient of x with the sum of the coefficients of x in Equation 1 and Equation 2.
D. An equation that replaces only the coefficient of y with the sum of the coefficients of y in Equation 1 and Equation 2.
E. The sum of a multiple of Equation 1 and Equation 2.
</span>A, B and E.
Adding and multiplying the terms allow them to keep working. However, you must make sure that each variable is changed each time. Not just one as in C and D.
Answer:
Divide 63/9=7
7*2= (the number of teachers) 14
There are 14 teachers for 63 students.
