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3 years ago

What is the answer to 6+9y-18=-3

1 answer:

7 0

6 + 9y - 18 = -3 Combine like terms (6 and -18)
9y - 12 = -3 Add 12 to both sides
9y = 9 Divide both sides by 9
y = 1

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I really need help with this Triangle problem.

julia-pushkina [17]

Answer:

x = 10

y = 20

Step-by-step explanation:

$\tan \: 30 \degree = \frac{x}{10 \sqrt{3} } \\ \\ \frac{1}{ \sqrt{3} } = \frac{x}{10 \sqrt{3} } \\ \\ \sqrt{3} x = 10 \sqrt{3} \\ \\ x = \frac{10 \sqrt{3} }{ \sqrt{3} } \\ \\ x = 10 \\ \\ \cos 30 \degree = \frac{10 \sqrt{3} }{y} \\ \\ \frac{ \sqrt{3} }{2} = \frac{10 \sqrt{3} }{y} \\ \\ y = 10 \sqrt{3} \times \frac{2}{ \sqrt{3} } \\ \\ y = 10 \times 2 \\ \\ y = 20$

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2 years ago

Which of the following statements identifies and explains whether the two triangles are similar?

nata0808 [166]

Answer:

I think it's "C"

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P.S. hope it helped. If you have any questions, I'll be glad to answer them❤

7 0

3 years ago

Read 2 more answers

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dimulka [17.4K]

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4 0

2 years ago

Factorize: (a+b)^2 + 4 (a+b)+ 4

pashok25 [27]

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3 years ago

If <ABC measures 100 and is inscribed in a circle O. find <BAO and <BCO

satela [25.4K]

Answer:

<BCO = <BAO = 20degrees

Step-by-step explanation:

If <ABC measures 100 and is inscribed in a circle O. find <BAO and <BCO

To get <BAO and <BCO, we need to get <AOC first.

From the figure, it can be seen that triangle ABC is an isosceles trinagle. Hence;

<BAC + <BCA + 100 = 180

Since <BAC = <BCA

<BAC + <BAC = 180 - 100

2<BAC = 80

<BAC = 80/2

<BAC = 40

Also;

<BAO = <BCO and <BAO = <BAC/2

<BAO = 40/2 = <BCO

Hence <BCO = <BAO = 20degrees

3 0

2 years ago