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kicyunya [14]
3 years ago
14

A point is plotted on the number line at 225 . A second point is plotted at −434 .

Mathematics
1 answer:
malfutka [58]3 years ago
7 0

Answer:

7 3/20

Step-by-step explanation:

I took the quiz.

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I need help what is this?
zhuklara [117]

Answer:

picture from Goldbach's conjecture.

Step-by-step explanation:

Goldbach's conjecture is one of the oldest and best-known unsolved problems in number theory and all of mathematics. It states:

Every even integer greater than 2 is the sum of two primes.

The conjecture has been shown to hold for all integers less than 4 × 10^18, but remains unproven despite considerable effort.

So on the red and blue axes you see primes. The list of black numbers are even numbers.

8 0
3 years ago
The scatter plot below shows the relationship between the length (x) in meters and mass f(x) in kg of a marine animal
Vlad [161]
F(x) = -9 + 10.3x probably.
It's definitely not the first or last option as they have negative gradients (i.e. negative x-coefficient) and so represent a negative correlation. The data given tells us there is a positive gradient and so a positive correlation.
It could be the second option as the second and third are not so vastly different but I would go for the third because it appears to most closely fit the data pattern.
6 0
3 years ago
Read 2 more answers
The lunch room at Diane’s school has a perimeter of 300 feet. The length of the room is 85 feet. What is the width of the room?
Mumz [18]

Answer:

65

Step-by-step explanation:

2w+ 2l = 300

2w + 170=300

2w= 130

w=65

3 0
3 years ago
Read 2 more answers
What is 41/44 times 12/29
Mnenie [13.5K]
The answer is 123/319
3 0
3 years ago
A sector of a circle of radius 80 mi has an area of 1600 mi2. Find the central angle (in radians) of the sector.
Butoxors [25]

Answer:

The central angle of the sector is 0.5 radian

Step-by-step explanation:

given;

radius of the circle, r = 80 mi

area of the sector, A = 1600 mi²

Area of sector is given by;

A = ¹/₂r²θ

where;

θ is the central angle (in radians) of the sector

\theta = \frac{2A}{r^2}\\\\\theta = \frac{2*1600}{80^2}\\\\  \theta = 0.5 \ radian

Therefore, the central angle of the sector is 0.5 radian

3 0
2 years ago
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