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Sedbober [7]
3 years ago
13

keely has $45.00 to spend on shirt. each shirt $8.50, and there is a $2.50 shipping fee for the order. how many shirts can she b

uy?
Mathematics
1 answer:
nydimaria [60]3 years ago
3 0
5 shirts is the correct answer
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Simplify the product.<br> (2+ V6) (2-16)
Nonamiya [84]
The answer should be -14(2+v^6) if I’m correct
6 0
3 years ago
A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the number of cakes sold per
HACTEHA [7]

Answer:

A) Revenue function = R(x) = (580x - 10x²)

Marginal Revenue function = (580 - 20x)

B) Fixed Cost = 900

Marginal Cost function = (300 + 50x)

C) Profit function = P(x) = (-35x² + 280x - 900)

D) The quantity that maximizes profit = 4

Step-by-step explanation:

Given,

The Price function for the cake = p = 580 - 10x

where x = number of cakes sold per day.

The total cost function is given as

C = (30 + 5x)² = (900 + 300x + 25x²)

where x = number of cakes sold per day.

Please note that all the calculations and functions obtained are done on a per day basis.

A) Find the revenue and marginal revenue functions [Hint: revenue is price multiplied by quantity i.e. revenue = price × quantity]

Revenue = R(x) = price × quantity = p × x

= (580 - 10x) × x = (580x - 10x²)

Marginal Revenue = (dR/dx)

= (d/dx) (580x - 10x²)

= (580 - 20x)

B) Find the fixed cost and marginal cost function [Hint: fixed cost does not change with quantity produced]

The total cost function is given as

C = (30 + 5x)² = (900 + 300x + 25x²)

The total cost function is a sum of the fixed cost and the variable cost.

The fixed cost is the unchanging part of the total cost function with changing levels of production (quantity produced), which is the term independent of x.

C(x) = 900 + 300x + 25x²

The only term independent of x is 900.

Hence, the fixed cost = 900

Marginal Cost function = (dC/dx)

= (d/dx) (900 + 300x + 25x²)

= (300 + 50x)

C) Find the profit function [Hint: profit is revenue minus total cost]

Profit = Revenue - Total Cost

Revenue = (580x - 10x²)

Total Cost = (900 + 300x + 25x²)

Profit = P(x)

= (580x - 10x²) - (900 + 300x + 25x²)

= 580x - 10x² - 900 - 300x - 25x²

= 280x - 35x² - 900

= (-35x² + 280x - 900)

D) Find the quantity that maximizes profit

To obtain this, we use differentiation analysis to obtain the maximum point of the Profit function.

At maximum point, (dP/dx) = 0 and (d²P/dx²) < 0

P(x) = (-35x² + 280x - 900)

(dP/dx) = -70x + 280 = 0

70x = 280

x = (280/70) = 4

(d²P/dx²) = -70 < 0

Hence, the point obtained truly corresponds to a maximum point of the profit function, P(x).

This quantity demanded obtained, is the quantity demanded that maximises the Profit function.

Hope this Helps!!!

8 0
3 years ago
Can Someone Help REAL QUICK Me. ? Please
bagirrra123 [75]

Answer: Option 3

Step-by-step explanation:

You can make equivalent fractions by multiplying or dividing both top and bottom by the same amount. You only multiply or divide, never add or subtract, to get an equivalent fraction.

I hope this helps.

5 0
3 years ago
How do I solve this???​
alexdok [17]

Answer:

Step-by-step explanation:

The equation of a proportional relationship: y = mx.

METHOD 1:

We know: If x and y are in a proportional relationshi, then the ratio y/x is constant

\dfrac{y}{x}=const.

We have P(3, 2) and Q(x, 6). Therefore

\dfrac{2}{3}=\dfrac{6}{x}             <em>cross multiply</em>

2x=(3)(6)              <em>divide both sides by 2</em>

x=\dfrac{18}{2}

x=9

METHOD 2:

<em>(look at the picture)</em>

The graph of y = mx is a straight line passes through the origin.

Step 1.

Plot point P(3, 2) on the graph.

Step 2.

Draw the line passes through he origin and point P.

Step 3.

Draw the line y = 6  <em>(6 from the coordinates of Q(x, 6))</em>

Step 4.

The intersection of lines is the point Q. Read the coordinte x.

3 0
3 years ago
Math question in pic above someone help!!!:D branlist for right answer
ollegr [7]

Answer:

A: up 3 units

Step-by-step explanation:

Hopefully this helps!

5 0
2 years ago
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