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ss7ja [257]
3 years ago
15

1/4(x+2)+4=12 x=? Help idk

Mathematics
2 answers:
Gnoma [55]3 years ago
5 0

\frac{1}{4}(x+2)+4=12

\frac{1}{4}(x+2)=8

x+2=32

x=30


ki77a [65]3 years ago
5 0

The answer is: x = 30

Step 1: Simplify [ 1/4 (x + 2) to x+2/4 ]

Step 2: Subtract 4 from both sides.

Step 3: Simplify 12-4 to 8

Step 4: Multiply both sides by 4

Step 5: Simply 8 x 4 to 32

Step 6: Subtract 2 from both sides

Step 7: Simplify 32 - 2 to 30.

Let me know if this helps! :)

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This is a CALCULUS question, "Derivatives As A function"
irina1246 [14]

Derivative Functions

The derivative function gives the derivative of a function at each point in the domain of the original function for which the derivative is defined. We can formally define a derivative function as follows.

Definition:

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4 0
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Which transformation of AB will produce a line segment A'B' that is parallel to AB?
lyudmila [28]

<em>Options:</em>

<em>Rotation of 180° about point B </em>

<em>Rotation of 90° about point b </em>

<em>Reflection over the x-axis </em>

<em>Translation down 2 units</em>

<em></em>

Answer:

Rotation of 180° about point B

<em></em>

Step-by-step explanation:

Considering coordinates of point B

Assume the coordinates of the line at point B is (x,y)

i.e. B = (x,y)

First, we need to determine the slope at point B

Taking coordinates about the origin.

The slope of B is:

m = \frac{y_2 - y_1}{x_2 - x_1}

Where

(x_1,y_1) = (0,0) --- origin

(x_2,y_2) = (x,y)

m = \frac{y_2 - y_1}{x_2 - x_1} becomes

m = \frac{y - 0}{x - 0}

m = \frac{y}{x}

Taking the options one after the other:

Option A.

When rotated by 180°, the resulting coordinates of B would be

B' = (-x,-y)

Taking the slope of B'

The slope of B is:

m = \frac{y_2 - y_1}{x_2 - x_1}

Where

(x_1,y_1) = (0,0) --- origin

(x_2,y_2) = (-x,-y)

m = \frac{y_2 - y_1}{x_2 - x_1} becomes

m = \frac{-y - 0}{-x - 0}

m = \frac{-y}{-x}

m = \frac{y}{x}

Notice that the slope of B and B' is the same;

m = \frac{y}{x}

<em>Hence:</em>

<em>Rotation of 180° about point B  answers the question</em>

<em></em>

<em>There's no need to check for other options</em>

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Step-by-step explanation:

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