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kirza4 [7]
3 years ago
6

Is h(x)=x^-2-36, quadratic?

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
6 0
No it is not quadratic. because when you graph it it is not a parabola 
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24 out of the 30 students in
kirill115 [55]
So if 24 out of the 30 kids rode the bus to school, that means that only six kids did not ride the bus.
We can set up a fraction with this situation! The denominator will be 30 because that is the total amount of kids overall.
Since we are trying to find the number of kids who DID NOT ride the bust, we have to subtract 30 from 24(30-24) to get how many kids did not take the bus.
This would give us a fraction of 6/24. Then we have to simplify it. It can be divided by 6 to the numerator and denominator giving us
1/4

The answer is 1/4 of students did not ride the bus.

Can I get true brainliest or a heart? Thanks, if you need more help please contact me in instagram.

@jessmyybest
6 0
3 years ago
Read 2 more answers
What is the maximum number of possible solutions for the system shown below?
julsineya [31]

\bf \begin{cases} 3x^2+y^2=4\\[-0.5em] \hrulefill\\ x^2+y=5\implies \boxed{y}=5-x^2 \end{cases} \\\\\\ \stackrel{\textit{substituting \boxed{y} in the 1st equation}}{3x^2+\left( \boxed{5-x^2} \right)^2=4}\implies 3x^2+25-10x^2+x^4=4 \\\\\\ x^4-8x^2+21=0\impliedby \begin{array}{llll} \textit{the degree of this polynomial}\\ \textit{is 4, and by the fundamental}\\ \textit{theorem of algebra, it can}\\ \textit{have \boxed{4} solutions at most} \end{array}

7 0
4 years ago
Sharon drops a rubber ball from a height of 48 feet. Every bounce sends the
BARSIC [14]

Answer:

132

Step-by-step explanation:

48 first hit and rises 24

24 second and rises 12

12 third hit and rises 6

6 forth hit

48+24+24+12+12+6+6= 132

5 0
3 years ago
Find the quotients?<br>Can someone help me please??​
Lynna [10]
I don’t know the answer sorry
5 0
3 years ago
If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true
aleksley [76]

- I think it's possibly this "The figure must be a square because the diagonals of a square bisect the right angles." but there's also "The figure must be a rhombus because it has exactly 2 pairs of congruent angles." buuut since the first one seems more better i'm assuming then that's probably the right answer.

5 0
4 years ago
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