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alexandr402 [8]
3 years ago
14

Please help. simplify each of the following. Write your answer as a fraction OR integer.

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
5 0

2^{-5} = \dfrac{1}{2^5} = \dfrac{1}{32}

3^{-2} = \dfrac{1}{3^2} = \dfrac{1}{9}

5^{-4} = \dfrac{1}{5^4} = \dfrac{1}{25^2} = \dfrac{1}{625}

(3^3)^{-2} = 3^{-6} = \dfrac{1}{3^6} = \dfrac{1}{9^3} = \dfrac{1}{729}

\dfrac{1}{4^{-4}} = 4^4 = 16^2 = 256

\dfrac{1}{2^{-5}} = 2^5 = 32

(5^{-3})^{-2}=5^6 = 15625 \quad

needed the calculator for that one

\dfrac{4}{5^{-2}} = 4 \cdot 5^{2} = 4 \cdot 25 =100

3^{6} \times 3^{-2} = 3^{6 - 2} = 3^4 = 9^2=81

4^{-8} \times 4^5 = 4^{-3} = \dfrac{1}{4^3} = \dfrac{1}{64}


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1. Case B

2.  9 cm³

3. 20 cm.

4. 4.5 m³

Step-by-step explanation:

Question 1: We are required to fit a drum having volume 14,000 cm³.

We know that the volume of cylinder = πr²h, where r is the radius and h is the height. So, according to the cases:

A. Here, r = 100 mm = 10 cm, h = 300 mm = 30 cm.

So, volume of the drum =  πr²h = \pi \times 10^{2} \times 30 = 9424.78 cm³.

We cannot put the given drum inside this drum.

B. Here, r = 200 mm = 20 cm, h = 30 cm.

So, volume of the drum =  πr²h = \pi \times 20^{2} \times 30 = 37699.11 cm³.

C. Here, r = 32 cm, h = 250 mm = 25 cm.

So, volume of the drum =  πr²h = \pi \times 32^{2} \times 25 = 80424.77 cm³.

Out of options B and C, the smallest volume is in CASE B i.e. 37699.11 cm³.

So, Case B is the correct option.

Question 2: We have the dimensions of the speaker as,

Length = 45 cm = 0.45 m, Width = 0.4 m, Height = 50 cm = 0.5 m

Now, Volume of a cuboid = L×W×H

Thus, volume of the speaker =  0.45 × 0.4 × 0.5 = 0.09 m³ = 9 cm³.

Question 3: We have that the volume of the speaker is 30,000 cm³.

Also, Length = 30 cm = 0.45 m, Height = 500 mm = 50 cm.

So, volume of the speaker = L×W×H

i.e. 30,000 = 30 × W × 50

i.e. W = \frac{30,000}{1500}

i.e. W = 20 cm.

Hence, the width of the speaker is 20 cm.

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Base= 2 m, Length = 3 m, Height = 1.5 m

So, the volume of prism = \frac{base\times height}{2} \times length

i.e. Volume =  \frac{2\times 1.5}{2} \times 3

i.e. Volume = 4.5

Thus, volume of the sand needed to be filled is 4.5 m³.

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