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Dima020 [189]
2 years ago
11

Find the area of the shape below. Break the larger shape into smaller pieces if needed.

Mathematics
1 answer:
NikAS [45]2 years ago
5 0

Answer:

116 Sq inches

Step-by-step explanation:

3×area of rectangle (l× b) + 2 area of triangle (1/2 b h)

3×32 + 2×1/2×4×5

96 + 20

116

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Dex estimates that 49,892 ÷ 0.89 is about 5,000. Is his estimate reasonable? Why or why not?
SVEN [57.7K]

Answer:yes

Step-by-step explanation:

because 0.89 is a very small number so itd be reasonable for it to be a large number

3 0
2 years ago
Read 2 more answers
Find the volume of a cylinder with radius 4 m. And height 3 m.
katovenus [111]
V =  \pi r^25

Plug in the values

r = 4 ; h = 3

V= \pi *4^2*3

V = 3.14 * 16 * 3

V = 150.72

So approximately 150.7
6 0
3 years ago
PLEASE HELP!!!!!
Ne4ueva [31]

Answer:

Equation: 30=2(x-2)+2(2x+3)

x:\frac{14}{3}

Step-by-step explanation:

By definition, the perimeter of a figure can be calculated by adding the lenghts of its sides.

Knowing this, you can write the following equation:

P=2(x-2)+2(2x+3) <em> [Equation 1]</em>

According to the data given in the exercise, the perimeter in feet of the fighter is:

P=30

Therefore, you can substitute this values into<em> [Equation 1]:</em>

30=2(x-2)+2(2x+3)

Finally, you must solve for "x" in order to find its value. This is:

30=6x+2\\\\30-2=6x\\\\\frac{28}{6}=x\\\\x=\frac{14}{3}

3 0
2 years ago
2. Select all the equations that have the same solution as the equation 3x - 12 = 24.
PIT_PIT [208]

Answer:

a and b

Step-by-step explanation:

15x-60=120

15x-60-60=120-60

15x=60

15x/15=60/15

x=4

3x=12

3x/3=12/3

x=4

8 0
3 years ago
The bearing of Q from P is 150
Lynna [10]

Answer:

(i) see first attached diagram

(ii) QR = 22.67 km (2 dp)

(iii) 243°

Step-by-step explanation:

A bearing is the angle in degrees measured clockwise from north.

<u />

<u>Part (i)</u>

see first attached diagram

<u>Part (ii)</u>

The angles marked in blue on the second attached diagram are Consecutive Interior Angles.  In this case they add to 180° as the North lines are parallel.

The sum of angles around a point is 360°

⇒ m∠QPR (shown in red on the second attached diagram) = 360 - 150 - (180 - 15) = 45°        

To calculate the distance between Q and R (marked in red on the attached diagram), use the cosine rule.

⇒ QR² = PR² + QP² - 2(PR)(QP)cos(QPR)

⇒ QR² = 32² + 24² - 2(32)(24)cos(45)

⇒ QR² = 513.8839841...

⇒ QR = √513.8839841...

⇒ QR = 22.67 km (2 dp)

<u>Part (iii)</u>

We need to find the angle marked in green on the third attached diagram.

To do this, we need to find the angle marked in pink and the angle marked in orange, then subtract them from 360°

Pink angle = 180 - 150 = 30° (using the same consecutive angle theorem as before)

Orange angle (o) using the sine rule:

⇒ sin(o)/32 = sin(45)/QR

⇒ sin(o) = 32sin(45)/22.67

⇒ sin(o) = 0.9981652337...

⇒ o = 86.52868176...°

Therefore, the green angle = 360 - 30 - 86.52868176... = 243° (nearest degree)

8 0
2 years ago
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