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Rudiy27
3 years ago
8

Determine the relationship between the point (1, –5) and the given system of inequalities.

Mathematics
2 answers:
zimovet [89]3 years ago
8 0
Algebraically, the point (1, -5) satisfies the first inequality, but it does not satisfy the second inequality because -5 is not greater than -5. Graphically, the point (1, -5) lies in the shaded area of the first inequality but lies on the dashed line of the second inequality, which is not inclusive. Therefore (1, -5) is not a solution to the given system of inequalities.
Darya [45]3 years ago
4 0
Y < = 3x + 2...subbing in (1,-5)
-5 < = 3(1) + 2
-5 < = 3 + 2
-5 < = 5 (true)

y > -2x - 3...subbing in (1,-5)
-5 > -2(1) - 3
-5 > -2 - 3
-5 > -5 (false)

response : Algebraically, the point (1,-5) satisfies the first inequality, but does not satisfy the second inequality because -5 is not greater then -5.Graphically, the point (1,-5) lies in the shaded area of the first inequality but lies on the dashed line of the second inequality, which is not inclusive. Therefore, (1,5) is not a solution to the given system of inequalities.

lol...ur sample response is the correct answer for this inequality...exactly


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The population is of 500 after 10.22 hours.

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The rate of change of the population of a certain organism is proportional to the population at time t, in hours.

This means that the population can be modeled by the following differential equation:

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Solving by separation of variables, then integrating both sides, we have that:

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At time t = 0 hours, the population is 300.

This means that K = 300. So

P(t) = 300e^{rt}

At time t = 24 hours, the population is 1000.

This means that P(24) = 1000. We use this to find the growth rate. So

P(t) = 300e^{rt}

1000 = 300e^{24r}

e^{24r} = \frac{1000}{300}

e^{24r} = \frac{10}{3}

\ln{e^{24r}} = \ln{\frac{10}{3}}

24r = \ln{\frac{10}{3}}

r = \frac{\ln{\frac{10}{3}}}{24}

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So

P(t) = 300e^{0.05t}

At what time t is the population 500?

This is t for which P(t) = 500. So

P(t) = 300e^{0.05t}

500 = 300e^{0.05t}

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\ln{e^{0.05t}} = \ln{\frac{5}{3}}

0.05t = \ln{\frac{5}{3}}

t = \frac{\ln{\frac{5}{3}}}{0.05}

t = 10.22

The population is of 500 after 10.22 hours.

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