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3 years ago

a bucket contains 50 lottery balls numbered 1-50.one is drawn at random.Find p(multiple of 6/2-digit number)

1 answer:

3 0

This is a problem of conditional probability that can be calculated by the formula:
P(B | A) = P(A ∩ B) / P(A)

We know that:
- between 1 and 50 there are 41 two-digit numbers, therefore
P(A) = 41/50 = 0.82

- between 1 and 50 there are 8 multiples of six, therefore
P(B) = 8/50 = 0.16

- between 1 and 50 there are 7 two-digits mutiples of six, therefore
P(A ∩ B) = 7/50 = 0.14

Now, we can calculate:
P(B | A) = P(A ∩ B) / P(A)
= 0.14 / 0.82
= 0.17

Therefore, the probability of getting a multiple of 6 if we draw a two-digit number is 17%.

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Fiesta28 [93]

Answer:

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Step-by-step explanation:

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3 years ago

What is the area of a circle with a diameter of 10

8_murik_8 [283]

It would be D because the formula is: pi r^2

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3 years ago

Read 2 more answers

The question is below

Cloud [144]

Answer:

See below.

Step-by-step explanation:

The first figure has 1 square. The second figure has a column of 2 squares added to the left. The third figure has a column of 3 squares added to the left. Each new figure has a column of squares added to the left containing the same number of squares as the number of the figure.

Figure 10 has 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55 squares.

The formula for adding n positive integers starting at 1 is:

1 + 2 + 3 + ... + n = n(n + 1)/2

For figure 55, n = 55.

n(n + 1)/2 = 55(56)/2 = 1540

Let's use the formula set equal to 190 and solve for n. If n is an integer, then we can.

n(n + 1)/2 = 190

n(n + 1) = 380

We know that 380 = 19 * 20, so n = 19.

Answer: yes

Use the formula above,

S = n(n + 1)/2, where S is the sum.

n(n + 1) = 1478

38 * 39 = 1482

37 * 38 = 1406

3 0

3 years ago

A school had a girl:boy ratio 5.4.

Ilya [14]

Answer:

164

The 982 part seems wrong. Are you sure it isn't 981?

around 436 if I use 981 instead. 982 would give a decimal and that would be kinda weird for a part human.

Step-by-step explanation:

You can divide the 205 by 5 to simplify the ratio down. 205/5 = 41. Then you can multiply by 4 to find then number of boys.

981

So you can add the 5 and 4 together to 9 and then divide 981 by 9 to get 109. Then you can multiply by 4 to get 436.

Hope this helps!

8 0

2 years ago

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago