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balu736 [363]
3 years ago
5

HELP!

Mathematics
1 answer:
creativ13 [48]3 years ago
7 0
AAS Theorem is what should be used I believe. The Sides are congruent and so are the 90 degree angles, the angles that are next to eachother on the left are evenly split by the transverse theorem. So AAS states that two angles and a side being equivelant on both triangles makes them congruent.
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Ritz can eat 8 apples in 15 minutes. How long does it take Ritz to eat 16 apples at the same rate?
natka813 [3]
The rate Ritz can eat apples is 8/15 apples per minute.

Set the rate (which is measured apples / minutes) equal to 16 apples / t minutes.

(8/15) = (16/t)

Cross multiply.

16*15 = 8t

t = 20

The answer is 30 minutes. You could solve the problem with basic reasoning as well. 16 is twice the number of apples as 8, so the time it takes to eat them will be double 15 minutes.
5 0
3 years ago
What is the true solution to 2 In ein 5x = 2 In 15
inessss [21]
Whyegevvdvevehuevdhehshh hsuwiuwhehehhehehev hehehehhehehevvshsisiehbebe uehehebbeheh hehehehhe. Hehehebvege. Hehehehevve be
6 0
3 years ago
3x - 12y = 24<br><br> Which of the following points represents the x and y intercepts?
umka21 [38]

Answer:

You need to categorize this to the form y=mx+c / y=mx+b

So,

12y=y & 3x=x

(Just let me know if u need further explanation or if this wasn't the ans. u were looking for)

7 0
3 years ago
Write the following in standard form:<br> Write<br> A = 4<br> B = 2<br> C = 7
bonufazy [111]

Answer:

4x + 2y = 7

Step-by-step explanation:

The standard form equation goes as follows: Ax + By = C

We know what A, B, and C is so all we need to do is fill them in.

7 0
3 years ago
Quadratic equations and complex numbers PLEASE HELPPPP ASAP
kondor19780726 [428]

we are given

27x^3-1=0

we can also write it as

(3x)^3-(1)^3=0

now, we can use factor formula

a^3-b^3=(a-b)(a^2+ab+b^2)

we can use above formula

we get  

(3x)^3-(1)^3=(3x-1)((3x)^2+3x\times 1+(1)^2)

now, we can simplify it

27x^3-1=(3x-1)(9x^2+3x+1)

now, we can set it to 0

27x^3-1=(3x-1)(9x^2+3x+1)=0

and then we can solve for x

(3x-1)(9x^2+3x+1)=0

3x-1=0

x=\frac{1}{3}

9x^2+3x+1=0

now, we can use quadratic formula

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

now, we can plug values

and we get

x=\frac{-3\pm \sqrt{3^2-4\cdot \:9\cdot \:1}}{2\cdot \:9}

x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}

So, we will get solution as

x=\frac{1}{3},\:x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}...............Answer

5 0
3 years ago
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