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2 years ago

Solve this questions:

Mathematics

1 answer:

In-s [12.5K]2 years ago

8 0

1 x=1/3 2 x =3/2 y =3/2

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= Initial Knowledge Check Rewrite the expression by factoring out (y+9). 3y^2 (y + 9) + 7(y+9)

alex41 [277]

Answer:

$3y {}^{2} (y + 9) + 7(y + 9) \\ = (y + 9)(3y { }^{2} + 7)$

6 0

3 years ago

What is 0,-4/7,-1/3,0.1,-0.1 in form least to greatest

Rashid [163]

Answer:

-4/7, -1/3, -0.1, 0, 0.1

Step-by-step explanation:

5 0

3 years ago

Solve: x + 1 < 5<br>Me confused and need help

natita [175]

Answer: x < 4

Step-by-step explanation: You are trying to isolate the variable, x, so you have to subtract 1 on both sides of the inequality. Then, you are left with x < 4.

4 0

3 years ago

A salesman gets a commission of 2.4% on sales up to sh. 100,000. He gets an additional commission of 1.5% on sales above this. C

emmainna [20.7K]

Answer:

Sh. 10,920

Step-by-step explanation:

Since the sales is above sh. 100,000,his commission is (2.4+1.5) 3.9%.

3.9% of 280,000= 10920.

Therefore, his commission is sh. 10,920

6 0

3 years ago

The number of bacteria in a certain culture doubled every hour. If there were 30 bacteria present in the culture initially, how

vichka [17]

Answer:

The number of bacteria after $8th$ will be $3840$

Step-by-step explanation:

Given the initially 30 bacteria present in the culture.

Also, the number of bacteria got doubled every hour.

So, using the equation

$A=A_0r^{n-1}$

Where $A$ is number of bacteria after $n$ hours.

$A_0$ is bacteria present initially.

$r$ is the common ration, in our problem it is given that bacteria doubles every hour. So, $r=2$

And $n$ is the number of hours. In our problem we need amount of bacteria at the end of $8th$ hours. So, $n=8$

Plugging values in the formula we get,

$A=30(2)^{8-1}\\A=30\times 2^7\\A=30\times 128\\A=3840$

So, number of bacteria after $8th$ will be $3840$

3 0

3 years ago

Solve this questions:​

Solve this questions: