Answer:
Let the 1st group be of students and 2nd group be of faculty.
n1 = 18
\bar{x}_{1} = 8.4
s1 = 7.3
n2 = 15
\bar{x}_{2} = 4.2
s2 = 3.8
1.
H0: =
HA: >
2.
Equality of variance test:
F = s12/s22
= 53.29/14.44
= 3.69
df-num = n1-1 = 17
df-den = n2-1 = 14
p-value = 0..008 < 0.05 i.e.H0 can be rejected and hence we can say that both populations do not have the same variances.
So, test-statistic will be calculated as follows:
[ Find the solution of this part in the attachment]
3.
df = 26
p-value = 0.0217
4.
E. It confirms the community college results because the p-value is much smaller.
Answer:
3 divide by 12= 4
Step-by-step explanation:
I think you would have to divide by 2 1/2
43 3/4
_______
2 1/2
Answer: 17 1/2
To check: 17 1/2 × 2 1/2 =43 1/2
Answer:
$56.33
Step-by-step explanation:
30% off of $69.98 is ($49.99) then add 15% which makes it $56.33 .!
Answer:
yes it is
Step-by-step explanation: