Answer:
The height of the pole is 167 m
Step-by-step explanation:
The given parameters are;
Increase in the length of the shadow = 90 m
Initial angle of elevation of the Sun = 58°
Final angle of elevation of the Sun = 36°
We have a triangle formed by the change in the length of the shadow and the rays from the two angle of elevation to the top of the pole giving an angle 22° opposite to the increase in the length of the shadow
We have by sin rule;
90/(sin (22°) = (Initial ray from the top of the pole to the end of the shadow's length)/(sin(122°)
Let the initial ray from the top of the pole to the end of the shadow's length = l₁
90/(sin (22°) = l₁/(sin(122°)
l₁ = 90/(sin (22°) ×(sin(122°) = 283.3 m
Therefore;
The height of the pole = 283.3 m × sin(36°) = 166.52 m
The height of the pole= 167 m to three significant figures.
Answer: 1,250
Step-by-step explanation:
Given: The total number of students in the school= 25,000
Since each class has 10 students , therefore, the number of classes in the school= 
Also, Each student takes 2 classes a day, thus the number of classes taken by total teachers in a day = 
Also, each teacher teaches 4 classes.
Then the number of teachers in the school =
Hence, the number of teachers are at Big Big School = 1,250
7.6375 =
1 Decimal Place = 7.6
<span>2 Decimal Place = 7.64
</span><span>3 Decimal Place = 7.638
</span><span>4 Decimal Place = 7.6375
</span>
So the answer is 7.64 .
The 3 rounds up because 7 is bigger than 5...
A=4 and b =29 hope this helps