Answer:
88.51 is the minimum score needed to receive a grade of A.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 73
Standard Deviation, σ = 11
We are given that the distribution of exam grades is a bell shaped distribution that is a normal distribution.
Formula:
We have to find the value of x such that the probability is 0.0793.
Calculation the value from standard normal z table, we have,
Hence, 88.51 is the minimum score needed to receive a grade of A.
To do this, change into common denominators. The common denominator is 21 so change the problem from 1/3 + 1/7 to 7/21 + 3/21. This gives you 10/21. It is already in simplest form.
1.
a) metres to centimetres :
multiply length by 100
b) metres to millimetres:
multiply length by 1000
c) kilograms to grams:
multiply the mass value by 1000
d) litres to millilitres :
multiply volume by 1000
2.
a) 3 m = 3× 100 = 300 cm
b) 28 cm = 28 × 10 = 280 mm
c) 2.4 km = 2.4 × 1000
= 24 × 10^-1 × 10^3
= 24 × 10^2 =2400 m
d) 485 mm =485 / 10
= 485 / 10 ^1
= 485 × 10 ^-1
= 48.5 cm
e) 35 cm = 35 / 100
= 35 /10^2
= 35 × 10 ^ -2
= 0.35 m
f) 2.4 m = 2.4 / 1000
= 24 × 10 ^-1 / 10^3
= 24 × 10^-1 × 10 ^-3
= 24 × 10 ^ -4
= 0.0024 km
g) 2495 mm = 2495 /1000
= 2495 /10^ 3
= 2495 × 10 ^-3
=2.495 m
Answer:
Slope = Y2 -Y1 / X2 - X1
Slope = -1 -3 / 8 --8
Slope = -4 / 16
Slope = -1 / 4
To calculate the equation we fill in this equation:
(y - y1) = slope • (x -x1)
We only need to choose 1 point so we'll choose (-8, 3)
(y - 3) = -1 / 4 * (x --8)
So the Equation equals
y = -1 / 4 x -2 + 3
y = -1 / 4x +1
Source:
http://www.1728.org/distance.htm
Step-by-step explanation:
The final equation is:
Further explanation:
The general form of equation of a line in slope-intercept form is:
Here m is the slope
Given
m=1
(x,y) = (-7,-4)
To find the value of b, we have to put the point in the equation
The final equation is:
Keywords: Slope-intercept form, equation of line
Learn more about slope-intercept form at:
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