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makvit [3.9K]
3 years ago
9

For the function f(x)= log5 3x-10 explain why x=2 is not in the domain

Mathematics
1 answer:
elena-s [515]3 years ago
3 0

Answer:


Step-by-step explanation:

The simple answer is that logs cannot be negative and if you insert a 2 where the x is located you get a negative. Logs have to be >= 0

[text]log_5 (3x-10) = log_5 (-4)[tex]

It all has to do with logs being tied to exponents and exponents being tied to logs. Actually an inverse of an exponent is a log.

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I need help with my math homework!
coldgirl [10]

Answer:

7.6(<em>a</em>+<em>b</em>) A.

8.205-2<em>d</em> D.

9. 0.05<em>n</em>+0.10<em>d</em>+0.25<em>q</em>=10 B.

7 0
3 years ago
Fiona and Camilla took a load of peaches to the farmer’s market. During the first hour, they sold ½ of the peaches plus ½ of a p
Lana71 [14]
<em>They took 101 peaches to market.</em>

<u>Check:</u>

In the 1st hour, they sold (101/2 + 1/2) = 102/2 = 51.  They had 50 left.

In the 2nd hour, they sold (50/3 + 1/3)=51/3=17.  They had (50-17)=33 left.

In the 3rd hour, they sold (33/4 + 3/4) = 36/4 = 9.  They had (33-9) = 24 left.

In the final hour, they sold (24/5 + 1/5) = 25/5 = 5.  They had (24-5) = 19 left.  yay!

Fiona and Camilla took their 19 remaining peaches and went home.  Sharing with
their parents and their brother Rowlf, each person had 3.8 peaches for dinner.
There was a lot of activity in the bathroom overnight.

================================================

The key to solving this one is to work it backwards.

-- They had 19 peaches left at the end of the day.

-- During the final hour, the 1/5 of a peach that they sold left them with 19,
so they had 19-1/5 before they sold the 1/5 of a peach.
The 19-1/5 was 4/5 of what they had at the beginning of the final hour.
So, at the beginning of the final hour, they had (5/4)x(19.2) = 24 .

-- During the 3rd hour, the 3/4 of a peach that they sold left them with 24,
so they had 24-3/4 before they sold the 3/4 of a peach.
The 24-3/4 was 3/4 of what they had at the beginning of that hour.
So, at the beginning of the 3rd hour, they had (4/3)x(24.75) = 33 .

Do the same for the 2nd hour.

Then do the same for the 1st hour.

And you'll work your way back up to 101 peaches.


4 0
4 years ago
An attacker at the base of a castle wall 4 m high throws a rock straight up with speed 7.5 m/s from a height of 1.5 m
Sergeu [11.5K]

Answer:

a) Yes, b) v\approx 2.686\,\frac{m}{s}, c) v_{o} \approx 7.002\,\frac{m}{s}

Step-by-step explanation:

a) The maximum height reached by the rock is:

\Delta y = \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(7.5\,\frac{m}{s} \right)^{2}}{2\cdot \left(-9.807\,\frac{m}{s^{2}} \right)}

\Delta y = 2.868\,m

y = 1.5\,m + 2.868\,m

y = 4.368\,m

Yes, the rock will exceed the top of the wall.

b) The speed when the rock reaches the top of the wall:

v = \sqrt{\left(7.5\,\frac{m}{s} \right)^{2}+2\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (4\,m-1.5\,m)}

v\approx 2.686\,\frac{m}{s}

c) The initial speed required so that stone does not exceed the top of the wall is:

v_{o} = \sqrt{\left(0\,\frac{m}{s} \right)^{2}-2\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (4\,m-1.5\,m) }

v_{o} \approx 7.002\,\frac{m}{s}

8 0
4 years ago
La respuesta correcta
Semenov [28]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
Solve for n
malfutka [58]
<span>(5 2/3+8 1/4)+9 3/4=n+18
</span><span>5 2/3+8 1/4+9 3/4=n+18
</span>5 2/3 + 18 = n + 18          | - 18
5 2/3 = n
7 0
3 years ago
Read 2 more answers
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