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3 years ago

Proper meaning for indices

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

8 0

Plural for index you are wecome bud

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From a point on the ground 12 ft. from the base of a flagpole, the angle of elevation of the top of the pole measures 53°. How t

torisob [31]

Answer:

4.75 feet

Step-by-step explanation:

Let the height of the flagpole be x

Sin 53 = x/12

x = 12 × Sin 53

x = 12 × 0.3959

x = 4.75 feet

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3 years ago

Distance between (5,4) and (1,-2)

vlada-n [284]

Answer:

4 units

Step-by-step explanation:

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3 years ago

A boy saves 80p a day, How much does it take him to save $40

laiz [17]

Answer:

50 Days

Step-by-step explanation:

I'm not sure what the unit "p" is, but I believe it is pennies so. $40/0.80 gives you 50 which is the amount of days it would take for you to get to $40 if you receive 80 cents a day

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2 years ago

Hurrryy!!! im on a timerrr

docker41 [41]

Answer:

3rd one

Step-by-step explanation:

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2 years ago

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago